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motikmotik
3 years ago
13

Can Anyone Please Do This It’s Math

Mathematics
2 answers:
Makovka662 [10]3 years ago
5 0

Answer:

1----> apple tree its (0.2,0.2)

2----> roses



Galina-37 [17]3 years ago
4 0

number one  is (0.2, 0.2) and then number two is the answer roses.

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HELP “Translate the following statement in algebraic expressions.”
Elanso [62]

Answer:

Step-by-step explanation:

It is translated exactly as you would read it. 4*y - 7

8 0
3 years ago
Maria rents a car for one day. The charge is $30 plus the $0.15 per mile. She wants to spend
Levart [38]

Answer:

Maria can drive 400 miles.

Step-by-step explanation:

30 + 0.15x = 90

0.15x = 60

x = 60/0.15

x = 400

7 0
3 years ago
I don't understand this question please help
Furkat [3]

Answer:

LM = 22

Step-by-step explanation:

11(44) = (LM)^2

484 = (LM)^2

LM = √484 = 22

8 0
2 years ago
Read 2 more answers
All athletes at the Olympic Games (OG) are tested for performance-enhancing steroid drug use. The basic Anabolic Steroid Test (A
Semenov [28]

Answer:

a ) the probability of using steroids and having a negative test is 0.5%

b) The probability of testing positive is 6.4%

c) The probability of not using steroids, given that the test is negative is 99.47%

d) No, they are not statistically indepent.

e) The probability that the athlete will either use steroids or test positive is 6.9%

Step-by-step explanation:

Let A be the event that the test result is positive and B the event that the athlete uses Steroids. We are given the following

P(A|B) = 90%, P(A|B^c) = 2%, P(B) = 5%

From which we deduce that

P(A^c|B) = 10%, P(B^c) = 95%

a) We are asked for the probability P(A^c\cap B). REcall the conditional probability formula that, given two events C,D the conditional probability P(C|D) = \frac{P(C\cap D)}{P(D)}. Then we have that

P(A^c\cap B) = P(A^c|B)P(B) = 10\% \cdot 5\%=0.5\%.

b) We are asked for the probability P(A). We can use the fact that given two mutually exclusive events(that is, whose intersection is empty) A,B the probability P(C) of an event is given by P(C) = P(C|A)P(A)+P(C|B)P(B). Then

P(A) = P(A|B)P(B)+P(A|B^c)P(B^c) = 90\%\cdot5\% + 2\% \cdot 95% = 6.4\%

c) We are asked for the probability P(B^c|A^c). Recall that P(A|B) = \frac{P(B|A)P(A)}{P(B)}. Then

P(B^c|A^c) = \frac{P(A^c|B^c)P(B^c)}{P(A^c)}= \frac{P(A^c|B^c)P(B^c)}{1-P(A)}= \frac{(1-P(A|B^c))P(B^c)}{1-P(A)}=\frac{98\%\cdot 95\%}{1-6.4\%}= 99.47\%

d) We say that two events A,B are statistically indepent if P(A|B) = P(A). Note that from point B the probability of testing negative is 1- 6.4% = 93.6%. Since 93.6% is different from 99.47% this means that testing positive and using steroids are not statistically independent.

e) We are asked for the probability P(A\cup B). We use the following

P(A\cupB) = P(A)+P(B)-P(A\cap B) = P(A) +P(B)-P(A|B)P(B) = 6.4\%+5\%-90\%\cdot 5\%=6.9\%

4 0
4 years ago
I mark brainlest for anybody who answer this question. just pls help
KATRIN_1 [288]

Answer:

A) 283.4mm^2

Step-by-step explanation:

Ok area of a circle

A=πr2

Radius is half of diameter

19/2=9.5

so

A=(3.14)9.5^2

A=283.385

round this nearest tenth

283.4mm^2

6 0
3 years ago
Read 2 more answers
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