P = W/t
W = Fd
P = Fd/t = F/t d
We have that
y = 2(0.45)^x
in this problem
2-----------> is the Coefficient
0.45-------> is the Base
<span>x-----------> is the Exponent
we know that
</span><span>If
the base is less than 1 (but always greater than 0), the function will be
exponential decay
</span>It is decay because as x values
increase, y values decrease.
<span>0.45 < 1 and 0.45 > 0
therefore
the equation
</span>y = 2(0.45)^x
represents <span>exponential
decay
</span>
the answer is
exponential decay<span>
</span>
In the 8th row there’s a Q and if u go sideways down it’s quadrilateral if u need more lmk!
Answer:
C = 5.
Step-by-step explanation:
First, you need to remember that:
For the function:
h(x) = Sinh(k*x)
We have:
h'(x) = k*Cosh(k*x)
and for the Cosh function:
g(x) = Cosh(k*x)
g'(x) = k*Cosh(k*x).
Now let's go to our problem:
We have f(x) = A*cosh(C*x) + B*Sinh(C*x)
We want to find the value of C such that:
f''(x) = 25*f(x)
So let's derive f(x):
f'(x) = A*C*Sinh(C*x) + B*C*Cosh(C*x)
and again:
f''(x) = A*C*C*Cosh(C*x) + B*C*C*Sinh(C*x)
f''(x) = C^2*(A*cosh(C*x) + B*Sinh(C*x)) = C^2*f(x)
And we wanted to get:
f''(x) = 25*f(x) = C^2*f(x)
then:
25 = C^2
√25 = C
And because we know that C > 0, we take the positive solution of the square root, then:
C = 5
Answer: 16, rational
Step-by-step explanation: because its a real number
