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Sphinxa [80]
3 years ago
13

PLEASE HELP ME I NEED THIS IN 15 MINUTES!!!

Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
6 0
The demensions are 4” wide 2” height and 12” length, forgive me if im wrong
algol [13]3 years ago
5 0

Answer:

4” wide 2” height and 12”

Step-by-step explanation:

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HELP<br> how to do this I will give Brainliest
Makovka662 [10]

Answer:

Does this help in any way?

Step-by-step explanation:

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4 0
3 years ago
Solve for x Rount to the nearest tenth if necessary
bulgar [2K]

Answer:

20.7

Step-by-step explanation:

7 0
2 years ago
(1) Cos AcosecA=cot A​
Mashutka [201]

Answer:

The Basic Identities are :

cosec(A) =  \frac{1}{ \sin(A) }

\tan(A)  =  \frac{ \sin(A) }{ \cos(A) }

\cot(A)  =  \frac{1}{ \tan(A) }  =  \frac{ \cos(A) }{ \sin(A) }

So for this question :

\cos(A)cosec(A) =  \cot(A)

l.s.h =  \cos(A)  \times  \frac{1}{ \sin(A) }

l.s.h =  \frac{ \cos(A) }{ \sin(A) }

l.sh =  \cot(A)  \: (proven)

7 0
3 years ago
An artist sells original hand painted greeting cards. He makes $2.50 profit on a small card and $4.00 profit on a large card. He
Marysya12 [62]
Since he sells 5 large cards for every 2 small, we can multiply the number of small cards he needs to sell by 2.5 to find how many large cards he needs to sell.

So let x=the number of small cards sold, and 2.5x=the number of large cards sold

The equation is:Total profit=x+(2.5x)

Since a small card is $2.5, a large card is $4, and the total profit will be $10,000 plug those in to make the equation:

10,000=2.5x+4(2.5x)

We can combine the x's to get 10,000=12.5x and then divide both sides by 12.5 to get x=800.

So he needs to sell 800 small cards.

Multiply that by that 2.5.

And he needs to sell 2000 large cards.

3 0
3 years ago
A​ town’s January high temperatures average 36 degrees​ (F) with a standard deviation of 10 degrees while in July the mean high
n200080 [17]

Answer:

55 degrees is more unusual in July as it is away from mean temperature as compared to January.

Step-by-step explanation:

We are given the following information in the question:

January:

Mean, μ = 36 degrees

Standard Deviation, σ = 10 degrees

July:

Mean, μ = 74 degrees

Standard Deviation, σ = 8 degrees

We calculate z scores corresponding to x = 55.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

January:

z_{score} = \displaystyle\frac{55-36}{10} = 1.9

July:

z_{score} = \displaystyle\frac{55-74}{8} = -2.375

Thus, 55 degrees is more unusual in July as it is away from mean temperature as compared to January.

3 0
3 years ago
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