Let the four consecutive integers be
x , x+1, x+2, x+3
ATQ, Their sum is 18






<h3>Now,</h3>
- 1st number = x = 3
- 2nd number = x+1 = 3+1 = 4
- 3rd number = x+2 = 3+2 = 5
- 4th number = x+3 = 3+3 = 6
<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>
The answer to your question is <span>8(n-3)=64</span>
A number that's bigger than 4.3 is the answer :)