Extra 10, 10 is half of what she ordered so she received an extra 50%
Answer:
♡ hi there! madeline here. ♡
- your answer is 10001
also, since I answered first, can I get the brainliest?
thank you, have a great day sandra!
✧・゚: *✧・゚:・゚✧*:・゚✧・゚: *✧・゚:・゚✧*:・゚✧
Step-by-step explanation:
Answer:
The graph has a removable discontinuity at x=-2.5 and asymptoe at x=2, and passes through (6,-3)
Step-by-step explanation:
A rational equation is a equation where

where both are polynomials and q(x) can't equal zero.
1. Discovering asymptotes. We need a asymptote at x=2 so we need a binomial factor of

in our denomiator.
So right now we have

2. Removable discontinues. This occurs when we have have the same binomial factor in both the numerator and denomiator.
We can model -2.5 as

So we have as of right now.

Now let see if this passes throught point (6,-3).


So this doesn't pass through -3 so we need another term in the numerator that will make 6,-3 apart of this graph.
If we have a variable r, in the numerator that will make this applicable, we would get

Plug in 6 for the x values.



So our rational equation will be

or

We can prove this by graphing
When you say sweet what does it equal