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cupoosta [38]
3 years ago
8

My new total was $60 after the discount and I still had to pay 5% for sales tax. What is the final total?

Mathematics
2 answers:
Len [333]3 years ago
5 0

Answer:

final total: 63

Step-by-step explanation:

60 times sales tax

60 times 0.05

3

60 + 3

63

ruslelena [56]3 years ago
5 0
The answer is :63

Explanation

60 times 0.05

3

60+3

63
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What is the common ratio for 128, 96, 72, 54,....
VLD [36.1K]

Answer:

Step-by-step explanation:

r=96/128=3/4

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3 years ago
The Falcone family is planning to drive from Syracuse, New York to Buffalo, New York. On a map with a scale of
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Answer:

The Falcones have to travel at 25 m/h to make the trip in 2 hours.

Step-by-step explanation:

In order to find the answer you have to use the formula to calculate speed:

speed=distance/time

distance=50 miles. The stament indicates that the distance between Syracuse and Buffalo is 1 inch and that the map has a scale of inch = 50 miles.

time=2 hours

Now, you can replace the values on the formula:

speed=50 miles/2 hours

speed=25 m/h

According to this, the answer is that the Falcones have to travel at 25 m/h to make the trip in 2 hours.

7 0
2 years ago
A trapezoid has an area of 13.5 square inches. If the bases are 3 and 6 inches what is the height?
liraira [26]
Well the formula is : b1+b2/2 (h)

so the height would be solved as : 
13.5 = 3+6/2 (h)
13.5 = 9/2 (h)
h = (13.5)/(9/2)
h = (13.5) x (2/9)  *reciprocal*
h = (27) / (9)
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5 0
3 years ago
15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.
Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = 30C5 = \frac{30 !}{(30-5)!5!} \\

30C5 = 142506 ways

Number of ways of selecting 5 good bulbs  from 26 bulbs = 26C5 = \frac{26 !}{(26-5)!5!} \\

26C5 = 65780 ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = \frac{26C4  * 4C1}{30C5}

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) =  \frac{26C3  * 4C2}{30C5}

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) +  Pr(2 defective) +  Pr(3 defective) +  Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) =  \frac{26C2  * 4C3}{30C5}

Pr(3 defective) = 0.009

Pr(4 defective) =  \frac{26C1  * 4C4}{30C5}

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0
3 years ago
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6 0
3 years ago
Read 2 more answers
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