Question

(look at the image) can i get help on this?

Answer 1

Answer:

I hope it helped u. Plz mark brainliest

Step-by-step explanation:

Answer 2

Step-by-step explanation:

1.

(2x-11)° = 105° (vertical angles)

2x - 11 = 105

2x = 105 + 11

2x = 116

x = 116/2

x = 58

$m\angle BEC = (2x - 11)\degree \\m\angle BEC = (2\times 58-11)\degree \\m\angle BEC = (116-11)\degree \\\huge m\angle BEC = 105\degree \\m\angle AEB =180\degree - 105\degree \\(straight \: line \: \angle 's) \\\huge m\angle AEB =75\degree \\m\angle CED=m\angle AEB = 75\degree\\ (vertical \:\angle' s)$

2.

$(6x + 19)\degree + x \degree = 180\degree \\(straight \: line \: \angle 's) \\(7x + 19) \degree = 180\degree\\7x + 19 = 180\\7x = 180 - 19\\7x = 161\degree \\x =\frac{161}{7}\\x = 23\\m\angle AEB=(6x + 19)\degree \\m\angle AEB=(6\times 23+ 19)\degree \\m\angle AEB=(138+ 19)\degree \\\huge m\angle AEB=157\degree \\m\angle CED=m\angle AEB = 157\degree\\ (vertical \:\angle' s) \\m\angle BEC = x\degree \\\huge m\angle BEC = 23\degree \\m\angle AED =m\angle BEC=23\degree \\(vertical \:\angle' s)$