Math help w/ triangles please
2 answers:
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Answer:
3, in both a), b)
Step-by-step explanation:
a) The slope of the line tangent to the curve that passes through the point (2,-10) is equal to the derivative of p at x=2.
Using differentiation rules (power rule and sum rule), the derivative of p(x) for any x is . In particular, the value we are looking for is
.
If you would like to compute the equation of the tangent line, we can use the point-slope equation to get
b) The instantaneus rate of change is also equal to the derivative of P at the point x=2, that is, P'(2). This is equal to .
Answer:
Option A: (4, -15).
Step-by-step explanation:
Given the quadratic function, y = x² - 8x + 1, where a = 1, b = -8, and c = 1:
<h3><u>Solve for the x-coordinate of the vertex:</u></h3>We can use the following equation to solve for the x-coordinate of the vertex:
Substitute the given values into the formula:
Hence, the x-coordinate of the vertex is 4.
<h3><u>Solve for the y-coordinate of the vertex:</u></h3>Next, substitute the x-coordinate of the vertex into the given quadratic function to solve for its corresponding y-coordinate:
y = x² - 8x + 1
y = (4)² - 8(4) + 1
y = 16 - 32 + 1
y = -15
Therefore, the vertex of the given quadratic function, y = x² - 8x + 1, is: x = 4, y = -15, or (4, -15). Thus, the correct answer is Option A: (4, -15).