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3 years ago

Math help w/ triangles please

Mathematics

2 answers:

Novosadov [1.4K]3 years ago

6 0

AAS
2 angles and 1 side (not in betweeen) are congruent so triangles are same
P and R are same
PQT and RQT are same
those are the 2 angles
the side is QT
therefor the triangles are
PQT and RQT
D is answer

BaLLatris [955]3 years ago

4 0

The answer to the triangle problem is C

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Find slope of the graph 9x-3y=15

LekaFEV [45]

<h3>Explanation</h3>

Convert the equation into slope-intercept form.

$y = mx + b$

where m = slope and b = y-intercept.

What we have to do is to make the y-term as the subject of equation.

$9x - 3y = 15 \\ 9x - 15 = 3y \\ \frac{9x - 15}{3} = y$

Simplify

$\frac{9x}{3} - \frac{15}{3} = y \\ 3x - 5 = y \\ y = 3x - 5$

From y = mx+b, the slope is 3.

<h3>Answer</h3>

$\large \boxed {slope = 3}$

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3 years ago

Will give brainliest lots of points A is the midpoint of LB,Lb =6x-17 and AB=2x+3

NARA [144]

A is the mid point ==> AL = AB = 2AB
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3 years ago

3. A piece of white oak has a densityof 0.77 g/cm and a mass of 100 g,what would be the volume of thesample? PLEASE HELP!

Nezavi [6.7K]

$\text{Volume}=129.87cm^3$

Explanation

Step 1

the density of an object is given by:

$\text{density}=\text{ }\frac{mass}{\text{volume}}$

Step 2

let

$\begin{gathered} \text{density}=0.77\frac{g}{cm^3} \\ \text{mass}=\text{ 100 g} \\ \end{gathered}$

Step 3

replace,

$\begin{gathered} \text{density}=\text{ }\frac{mass}{\text{volume}} \\ 0.77\frac{g}{cm^3}=\frac{100g}{\text{volume}} \\ \text{volume}\cdot0.77\frac{g}{cm^3}=\text{1}00\text{ g} \\ \\ \text{Volume}=\frac{100\text{ g}}{0.77\frac{g}{cm^3}} \\ \text{Volume}=129.87cm^3 \end{gathered}$

I hope this helps you

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1 year ago

Show work how you know it’s a function or not a function for each problem. PLEASE SOMEONE HELP ME OUT

Fudgin [204]

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Step-by-step explanation:

For it to be a function, each value of x has to map onto one value of y.

This is a function.
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2 years ago

Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon

leva [86]

Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = proportion of households that have three cell phones NOT known.

So, Null Hypothesis, $H_0$ : p = 30% {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, $H_A$ : p $\neq$ 30% {means that the actual percentage of households different from 30%}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of households having three cell phones = $\frac{43}{150}$ = 0.29

n = sample of households = 150

So, the test statistics = $\frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }$

= -0.27

The value of z test statistic is -0.27.

Also, P-value of the test statistics is given by;

P-value = P(Z < -0.27) = 1 - P(Z $\leq$ 0.27)

= 1 - 0.6064 = 0.3936

Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the actual percentage of households is equal to 30%.

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3 years ago