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nevsk [136]
4 years ago
11

Dummy forgot his pin code. 20% of his pin code was 246.8 what was dummy pin code?

Mathematics
1 answer:
Vlada [557]4 years ago
8 0
The dummies pin code would be 49.36.
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How do I do this again ?
AVprozaik [17]

The formula for the area of a trapezoid is a=1/2(b1+b2)h

So 10*5 = 50 *4 = 200 then divided by 2 is 100 so the answer is 100

7 0
4 years ago
1. Write the equation in standard form. Identify the important features of the graph:
NeTakaya

Answer:

  1. (x-4.5)^2 +(y +5)^2 = 30.25
  2. x = (1/8)y^2 +(1/2)y +(1/2)
  3. y^2/36 -x^2/64 = 1
  4. x^2/16 +y^2/25 = 1

Step-by-step explanation:

1. Complete the square for both x and y by adding a constant equal to the square of half the linear term coefficient. Subtract 15, and rearrange to standard form.

  (x^2 -9x +4.5^2) +(y^2 +10y +5^2) = 4.5^2 +5^2 -15

  (x -4.5)^2 +(y +5)^2 = 30.25 . . . . . write in standard form

Important features: center = (4.5, -5); radius = 5.5.

__

2. To put this in the form x=f(y), we need to add 8x, then divide by 8.

  x = (1/8)y^2 +(1/2)y +(1/2)

Important features: vertex = (0, -2); focus = (2, -2); horizontal compression factor = 1/8.

__

3. We want y^2/a^2 -x^2/b^2 = 1 with a=36 and b=(36/(3/4)^2) = 64:

  y^2/36 -x^2/64 = 1

__

4. In the form below, "a" is the semi-axis in the x-direction. Here, that is 8/2 = 4. "b" is the semi-axis in the y-direction, which is 5 in this case. We want x^2/a^2 +y^2/b^2 = 1 with a=4 and b=5.

  x^2/16 +b^2/25 = 1

_____

The first attachment shows the circle and parabola; the second shows the hyperbola and ellipse.

6 0
3 years ago
A composite solid consists of a cube with edges of length 6cm and a square pyramid with base edges of length 6cm and height of 6
icang [17]

Answer: The volume of the solid is 324 cm³

Step-by-step explanation:

Formula for determining the volume if a cube is s³

Where s represents the length of each side of the cube.

From the information given, s = 6 cm

Volume = 6³ = 216 cm³

The formula for determining the volume of the square base pyramid is expressed as

Volume = Area × height × 1/3

From the information given,

Length of square base = 6 cm

Height = 6 cm

Area of square base = 6² = 36 cm²

Volume of square base pyramid

= 36 × 6 × 1/3 = 108 cm³

The volume of the solid would be the sum of the volume of the cube and the volume of the square base pyramid. It becomes

216 + 108 = 324 cm³

5 0
4 years ago
If one postage stamp costs $0.85, how<br> much does a book of 25 stamps cost?
aniked [119]

Answer: $21.25

Step-by-step explanation:

0.85 x 25

5 0
4 years ago
Read 2 more answers
Need to find volume, step by step explanation pls <br><br><br><br>​
worty [1.4K]

Given:

A figure of combination of hemisphere, cylinder and cone.

Radius of hemisphere, cylinder and cone = 6 units.

Height of cylinder = 12 units

Slant height of cone = 10 units.

To find:

The volume of the given figure.

Solution:

Volume of hemisphere is:

V_1=\dfrac{2}{3}\pi r^3

Where, r is the radius of the hemisphere.

V_1=\dfrac{2}{3}(3.14)(6)^3

V_1=\dfrac{6.28}{3}(216)

V_1=452.16

Volume of cylinder is:

V_2=\pi r^2h

Where, r is the radius of the cylinder and h is the height of the cylinder.

V_2=(3.14)(6)^2(12)

V_2=(3.14)(36)(12)

V_2=1356.48

We know that,

l^2=r^2+h^2                               [Pythagoras theorem]

Where, l is length, r is the radius and h is the height of the cone.

(10)^2=(6)^2+h^2

100-36=h^2

\sqrt{64}=h

8=h

Volume of cone is:

V_3=\dfrac{1}{3}\pi r^2h

Where, r is the radius of the cone and h is the height of the cone.

V_3=\dfrac{1}{3}(3.14)(6)^2(8)

V_3=\dfrac{25.12}{3}(36)

V_3=301.44

Now, the volume of the combined figure is:

V=V_1+V_2+V_3

V=452.16+1356.48+301.44

V=2110.08

Therefore, the volume of the given figure is 2110.08 cubic units.

7 0
3 years ago
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