Answer:
Step-by-step explanation:
Given that 10000 times a fair coin is flipped. Since fair coin prob for head of tail =0.5
If tail comes it will be taken as 1. Hence for the sum to be less than 5000, no of heads <5000
Since trials are large we approximate to normal with mean = np = 5000 and variance = np(1-p) = 2500
Thus no of heads x is normal with (5000, 50)
Since this prob is less than 0.5 only minimum amount to be bet i.e. 1 dollar
If sum of coins <5100, then Z =
P(Z<2) = 0.9500
This time we can bet maximum of 100 dollars as probability is very high nearer to 1.
Answer:
last option is the answer; all values greater than 12
Step-by-step explanation:
2/3x - 5 > 3
2/3x > 8
x > 24/2
x > 12
39x98 is 3,822. do you need to know how I got that?
You have 4 marbles and you can get 3 combinaisons of two marbles for each one.
So 4*3 = 12.
There are 12 outcomes. The answer would be D.
Hope this helps !
Photon
Number one 8^4*8^6=
(8*8*8*8)*(8*8*8*8*8*8)=
4096*262144= [1,073,741,824]