Answer:
the top answer.............
Okay lets create an eqn from that information
A first int, B second int, C third int, D fourth int.
B = A + 2
C = A + 4
D = A + 6
A is the smallest integer
B + D = 0.5 (A + C)
Now lets substitute
(A + 2) + (A + 6) = 0.5(A + (A + 4))
now lets dist
2a + 8 = 0.5(2a +4)
2a + 8 = a + 2
a + 8 = 2
a = -6
B = -6 +2
B = -4
C = -6 + 4
C = -2
D = -6 + 6
D = 0
Now using B + D = 0.5(A + C)
-4 + 0 = 0.5(-6 + (-2))
-4 = 0.5 (-8)
-4 = -4
Correct
Therefore, First integer is -6, second integer is -4, third integer is -2 and fourth integer is 0
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First, you'd work out the centre value
It would be the opposite value to what is in the brackets
Thus, the centre value is (2, -4)
Plot this value on a graph
In order to find the radius, you must square root the 25
Thus, the radius would be 5
Plot some points with a radius of 5 from the centre and then draw the circle
Have A Nice Day ❤
Stay Brainly! ヅ
- Ally ✧
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<h2>Explanation:</h2>
Here we need to solve some expressions. Remember the following rules:
Then, from the left side:
from the right side:
Hi Cuppykitty!!
30% I believe because we still have those to rectangles on the side
Hope this helps :)
