Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
8r+(12-3)p-7------>8r+9p-7
Answer:
i think its letter B. 20% down payment
No this is not a function because 4 is used twice on the y side
Answer:
C
Step-by-step explanation:
Step-by-step explanation:
$15x8=$120 = money earned at first job
$12x3=$36 = money earned at second job
$120+$36=$156 =total earned
