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defon
3 years ago
5

Which of the following is true about the sampling distribution of means? Sampling distribution of the mean is always right skewe

d since means cannot be smaller than 0. Sampling distributions of means get closer to normality as the sample size increases. Sampling distributions of means are always nearly normal. Shape of the sampling distribution of means is always the same shape as the population distribution, no matter what the sample size is.
Mathematics
1 answer:
vfiekz [6]3 years ago
5 0
I don’t think I have a a lot to do and then it will be the day that because I’m not going out because I’m going out of the state and then it would be better to get it a day or so please thank me thank for it I don’t think know answer question question because you lord lord please thank the god for the gods and god that he did not gave you thank the lord for that answer please please answer answer question answer answer me question
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A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard d
bagirrra123 [75]

The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

<h3>
How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>

Suppose that we have:

  • Sample size n > 30
  • Sample mean = \overline{x}
  • Sample standard deviation = s
  • Population standard deviation = \sigma
  • Level of significance = \alpha

Then the confidence interval is obtained as

  • Case 1: Population standard deviation is known

\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}

  • Case 2: Population standard deviation is unknown.

\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}

For this case, we're given that:

  • Sample size n = 90 > 30
  • Sample mean = \overline{x} = 138
  • Sample standard deviation = s = 34
  • Level of significance = \alpha = 100% - confidence = 100% - 90% = 10% = 0.1 (converted percent to decimal).

At this level of significance, the critical value of Z is: Z_{0.1/2} = ±1.645

Thus, we get:

CI = \overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\\CI = 138 \pm 1.645\times \dfrac{34}{\sqrt{90}}\\\\CI \approx 138 \pm 5.896\\CI \approx [138 - 5.896, 138 + 5.896]\\CI \approx [132.104, 143.896] \approx [130.10, 143.90]

Thus, the 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

Learn more about confidence interval for population mean from large samples here:

brainly.com/question/13770164

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2 years ago
Which set of sides would make a right angle?
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The answer is 5,12,13 as when you plug these into the Pythagorean theorem :
5^2 + 12^2 = 13^2
25 + 144 = 169
13^2 = 169
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