A mandatory competency test for high school sophomores has a normal distribution with a mean of 400 and a standard deviation of
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V + 
= 8
First, simplify to 3. / Your problem should look like: v + 3 = 8.
Second, subtract 3 from both sides. / Your problem should look like: v = 8 - 3.
Third, simplify 8 - 3 to 5. / Your problem should look like: v = 5, which is your answer.
First, simplify
Second, subtract 3 from both sides. / Your problem should look like: v = 8 - 3.
Third, simplify 8 - 3 to 5. / Your problem should look like: v = 5, which is your answer.
now, how do we get the coefficients? well, the first coefficient is 1, any subsequent is " the product of the current terms's coefficient and the exponent of the first element, divided by the exponent of the second element in the next term", now that's a mouthful, but for example,
how did get 210 for the 5th expanded term? well is just 120 * 7 / 4
how about 252 of the 6th term? 210 * 6 / 5.
how about 45 of the 9th one? 120 * 3 / 8.
of course, the exponents for each is simple, as you'd already know from the binomial theorem.
so, just expand away the 9th expanded term.