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allochka39001 [22]
3 years ago
13

Answer this please 20 points

Mathematics
1 answer:
8090 [49]3 years ago
7 0

Do you know What topic this is ?


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What is 2x=16 i to explan it
valentina_108 [34]

Answer:

2x=16

/2    /2

x=8

Step-by-step explanation:

just need to isolate the x, by dividing by two on both sides.

hope this helps :)

3 0
3 years ago
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If Julie needs 3 1/4 cups of oatmeal, how many 1/4 cups of oatmeal will she use?
Romashka-Z-Leto [24]
Julie will use 13 1/4 cups of oatmeal.
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3 years ago
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Data Entry - No Scoring During your procedure to determine the uncalibrated volume near the stopcock of your buret, what was the
DaniilM [7]

Answer:

0.025 grams

Step-by-step explanation:

The water in the stopcock has a volume of 25 mL initially, After that, the whole water was drained out. So we have:

Volume of drained water = (25 mL)(1 x 10⁻⁶ m³/1 mL)

Volume of drained water = 25 x 10⁻⁶ m³

Density of drained water = 1000 kg/m³

So, for the mass of drained water:

Density of drained water = Mass of drained water/Volume of drained water

Mass of drained water = (Density of drained water)(Volume of drained water)

Mass of drained water = (1000 kg/m³)(25 x 10⁻⁶ m³)

<u>Mass of drained water = 0.025 gram</u>

Density

4 0
3 years ago
Which is one reason why this expression is equal to 0?
Sphinxa [80]

Answer:

There is no expression

6 0
3 years ago
Find each measurement indicated round your answers to the nearest tenth. Part 1d. NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW
valkas [14]

Answer:

see explanation

Step-by-step explanation:

Using the Sine rule in all 3 questions

(1)

\frac{a}{sinA} = \frac{b}{sinB} , substitute values , firstly calculating ∠ B

[ ∠ B = 180° - (78 + 49)° = 180° - 127° = 53° ]

\frac{a}{sin78} = \frac{18}{sin53} ( cross- multiply )

a sin53° = 18 sin78° ( divide both sides by sin53° )

a = \frac{18sin78}{sin53} ≈ 22.0 ( to the nearest tenth )

(3)

\frac{c}{sinC} = \frac{a}{sinA} , substitute values

\frac{35}{sinC} = \frac{45}{sin134} ( cross- multiply )

45 sinC = 35 sin134° ( divide both sides by 35 )

sinC = \frac{35sin134}{45} , then

∠ C = sin^{-1} ( \frac{35sin134}{45} ) ≈ 34.0° ( to the nearest tenth )

(5)

Calculate the measure of ∠ B

∠ B = 180° - (38 + 92)° = 180° - 130° = 50°

\frac{a}{sinA} = \frac{b}{sinB} , substitute values

\frac{BC}{sin38} = \frac{10}{sin50} ( cross- multiply )

BC sin50° = 10 sin38° ( divide both sides by sin50° )

BC = \frac{10sin38}{sin50} ≈ 8.0 ( to the nearest tenth )

3 0
3 years ago
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