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allochka39001 [22]
3 years ago
13

Answer this please 20 points

Mathematics
1 answer:
8090 [49]3 years ago
7 0

Do you know What topic this is ?


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The reliability of a piece of equipment is frequently defined to be the probability, P, that the equipment performs its intended
Sergio [31]

Answer:

a. y=1

b. Mean= 0.5; variance=0.5

c. In the first instance, the probability that p > 0.95 would mean that we are looking for the area of the rectangle with a height of 1 between 0.95 and 1, which implies it has length 0.05.

Therefore, the area is length × height, which is 0.05 ×1 = 0.05.

Second case, the probability that p is less than 0.95 would then be one minus the probability that p is greater than 0.95, so 1 - 0.05 = 0.95

D. a horizontal line at 20 between 0.90 and 0.95, and will be zero outside of this range.

Step-by-step explanation:

With the use of probability distribution, the probability that the equipment performs has a uniform distribution with minimum 0 and maximum 1.

a) The graph of the probability distribution will be 0 outside of the range of 0 to 1, so therefore y = 0. Inside the interval from 0 to 1, it will be constant (which is a horizontal line) with height 1÷(1-0) = 1, therefore y = 1.

b) The mean of the uniform is (maximum+minimum)/2.

Therefore, (1+0)/2 = 1/2 or 0.5.

The variance of the uniform is

(maximum-minimum)^2/12,

so (1-0)^2/12 = 1/12.

c) Since the probability distribution is rectangular, you can find probabilities by recalling the area of a rectangle which is: area = length × breadth.

In the first instance, the probability that p > 0.95 would mean that we are looking for the area of the rectangle with a height of 1 between 0.95 and 1, which implies it has length 0.05.

Therefore, the area is length × breadth, which is 0.05 ×1 = 0.05.

In the second case, the probability that p is less than 0.95 would then be one minus the probability that p is greater than 0.95, so 1 - 0.05 = 0.95.

d) If it is known that p is between 0.90 and 0.95, without the value, then we would assume that p has a uniform distribution between 0.90 and 0.95 since p originally had a uniform distribution.

In this case,

f(p) =

1/(0.95-0.90) = 20, 0.90 < p < 0.95,

0, otherwise.

In a nutshell, this function will have a horizontal line at 20 between 0.90 and 0.95, and will be zero outside of this range.

6 0
3 years ago
What is the distribution property of 4 times 37
hjlf

Answer:

  4(30 +7) = 120 +28 = 148

Step-by-step explanation:

When applying the distributive property to integers, we usually break them apart according to place value. That is not the only way it can be done.

  4×37 = 4(30 +7) = 4·30 +4·7 = 120 +28 = 148

___

You can also break apart 37 other ways:

  4×37 = 4(35 +2) = 4·35 +4·2 = 140 +8 = 148

  4×37 = 4(40 -3) = 4·40 -4·3 = 160 -12 = 148

Or, you can break apart 4:

  37×4 = 37(2 +2) = 37·2 +37·2 = 74 +74 = 148

_____

The distributive property is usually written in generic form as ...

  a(b+c) = ab +ac

Then you may want to stop after the first couple of steps:

  4(30 +7) = 4·30 +4·7

We can't tell if you're suppose to evaluate the expression or not. Check your reference materials for an example of this kind of problem.

7 0
2 years ago
A ramp with a constant incline is made to connect a driveway to a front door. At a point 4 feet from the driveway, the height of
harkovskaia [24]
Let A(4,12) and B(6,18)

RATE OF CHANGE = m = (y₂ - y₁) / (x₂ - x₁) = (18-12)/ (6-4)

m= 6/2 or m = 3
4 0
2 years ago
Read 2 more answers
Twenty percent of a number is 14. find the number
7nadin3 [17]
The answer is:   70  .
___________________________________________
Explanation:
_________________________________

(20/100) x = 14;  solve for "x".

(20/100) = 2/10 = 1/5 ; 

(1/5) x = 14

x/5 = 14 ; 

x = 14 * 5 ; 

x = 70 .  The answer is:  70 .
___________________________________
5 0
3 years ago
Read 2 more answers
Use properties to find the sum or product of 93+(68+7)
zaharov [31]
93 + (68 + 7)
93 + 75
168
7 0
3 years ago
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