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mina [271]
1 year ago
14

If sin (90° - α) = BC /CA,write down the ratio of sina.​

Mathematics
1 answer:
Papessa [141]1 year ago
7 0

Answer:

Step-by-step explanation:

sin(90-a)=cos

cos = angle adjacent

theta=BC/CA

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The schematic of a rectangular patio is drawn 1/4 inch to 1 feet. if the patio is 18 feet long, what is the measure of the patio
Aleksandr-060686 [28]
Try 4.5 inches. You take 18, divide it by four you get 4.5. I divided by 4 because of the 1/4 inch by 1 foot. Minus 2 from 18, you get the next closest dividend of 4 and that's 16. 16 divided by 4 is 4. 2 are left over to make .5. you get 4.5
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3 years ago
3. The Luxor hotel, in Las Vegas, is a square pyramid with lateral faces consisting of black, glassed mirrored panes. The buildi
krek1111 [17]
Given: 
Square pyramid with lateral faces.
646 ft wide at the base.
350 ft high.

Because of the term lateral faces, we need to get the lateral area of the square pyramid.

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L.A. = 646 ft √(646ft)² + 4 (350ft)²
L.A. = 646 ft √417,316 ft² + 4 (122,500 ft²)
L.A. = 646 ft √417,316 ft² + 490,000 ft²
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3 0
3 years ago
Circumference and area of 7ft​
nikdorinn [45]
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5 0
2 years ago
Please someone tell me the answers to these I dont remember how to do it ​
Delvig [45]

Answer:

1)  (3 - 6x)(-8) = (-8)(3) - (-8)(6x) = -24 - (-48x) = -24 + 48x = 48x - 24

2) (-12)(2x - 3) = (-12)(2x) - (-12)(3) = -24x - (-36) = -24x + 36 = 36 -  24x

3) (10 - 2x)9 = (9)(10) - (9)(2x) = 90 - 18x

4) (-5)(11x - 2) = (-5)(11x) - (-5)(2) = -55x - (-10) = -55x + 10 = 10 - 55x

5) (1 - 9x)(-10) = (-10)(1) - (-10)(9x) = -10 - (-90x) = -10 + 90x = 90x - 10

6) (-6)(x + 8) = (-6)(x) + (-6)(8) = -6x + (-48) = -6x - 48

7) (-4 + 3x)(-8) = (-8)(-4) + (-8)(3x) = 32 + (-24x) = 32 - 24x

8) (-5)(1 - 11x) = (-5)(1) - (-5)(11x) = -5 - (-55x) = -5 + 55x = 55x -5

9) (-12x + 14)(-5) = (-5)(-12x) + (-5)(14) = 60x + (-70) = 60x - 70

Step-by-step explanation:

The distributive property is a(b + c) = ab + ac

8 0
2 years ago
Plz help w this math problem
Svetllana [295]

Answer:

• for x = 2a√t, make t the subject:

{ \tt{x = 2a \sqrt{t} }} \\  \\ { \tt{ \sqrt{t}  =  \frac{x}{2a} }} \\  \\ { \boxed{ \tt{t =  \frac{ {x}^{2} }{4 {a}^{2} } }}}

• then find y:

{ \tt{y =  {ar}^{2}  - 2at}} \\  \\ { \tt{y =  {ar}^{2} - 2a( \frac{ {x}^{2} }{4 {a}^{2} } ) }} \\  \\ { \boxed{ \tt{y =  {ar}^{2} -  \frac{ {x}^{2} }{2a}  }}}

6 0
3 years ago
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