The domain of a function is where we have a value for x.
Since that's the case the domain of f(x) = {x e R / 1 ≤ x < 5}
We see that we have a value for x = 1 cuz we have a filled circle, but we don't have a value for x = 5, look at the unfilled circle
So, our x can vary between 1 and 5, but can't be 5.
Answer:

Step-by-step explanation:
Suppose h is the inverse of f then
f(x) = y ⇔ h(y) = x
f(x) = y ⇔ 4x = y ⇔ x = y/4
and since x = h(y) then h(y) = y/4
then we can write :

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Answer:
3x^2 + 3xy/2 - 7xy^2/2
Step-by-step explanation:
So we know the perimeter is 20x^2 + xy - 7y^2,
To find any perimeter you need 2l + 2w = P so,
One of the sides is 7x^2 - xy
First plug in the values,
2(7x^2-xy) + 2w = 20x^2 + xy - 7y^2
Multiply,
14x^2-2xy + 2w = 20x^2 + xy - 7y^2
Subtract,
14x^2 - 2xy - 14x^2 + 2xy + 2w = 20x^2 + xy - 7y^2 - 14x^2 + 2xy
2w = 6x^2 + 3xy - 7y^2
w = 3x^2 + 3xy/2 - 7xy^2/2
Answer:
They are skew lines.
Step-by-step explanation:
Which statement is true about lines a and b?
They are parallel lines.
They are perpendicular lines.
They are skew lines.
They will intersect.
As they both are in different directions they are skew lines .
Skew lines are not parallel neither they .They are also not co planar i.e they lie in different planes.
We have two plane Q and R . We have two line a and b on the different planes Q and R. Both planes are parallel but the lines a and b are in different directions. Therefore they are skew lines . They do not intersect and are also not parallel neither co planar.
Answer:
Step-by-step explanation:
Putting value of x = 2 in the equation
F(2) = 2(2) - 6
= 4 - 6
= - 2