It's just an equation, the number you're looking for is X, and then turn the words into an solvable equation with respect to X.
7X + 3 = 39 - 2X
9X = 39 -3 = 36
X = 4
Answer:
B is the answer.
Step-by-step explanation:
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Triangles cannot have two 90 degrees because that would add up to 180 and triangles need 3 angles to add to 180
You can't have an obtuse angle and a right angle. say the obtuse angle was 110, and a right angle is 90. 110 + 90 is more than 180.
Two obtuse angles would be more than 180.
This leaves us with B being correct, because you can have an obtuse angle and an acute angle, and it can be less than 180 degrees.
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#teamtrees #WAP (Water And Plant)
Answer:
45 grams of cheese
Explantation:
9 grams of cheese onto each plate x 5 plates = 45 grams of cheese
Hopefully this helps :3 Sorry If wrong :( plz mark brainiest if correct :D Your bootiful/handsome! Have a great day luv <3
-Bee~
Answer:
Tan E = 2 / 7.75
Sin G = 7.75 / 8
Sec G = 4
Step-by-step explanation:
Find the attached document for better illustration of the triangle
Assuming the hypothenus of the triangle is 8 = EG since it's the longest side of the triangle.
FG = 2 = opposite side of the triangle.
We can use pythagorean theorem to find the adjacent of the triangle since we already know two sides.
EG² = FG² + EF²
EF² = EG² - FG²
EF² = 8² - 2²
EF² = 64 - 4
EF² = 60
EF = √(60)
EF = 7.7459 = 7.75
To find the respective trignometric ratio, we can use the relation SOH CAH TOA
Sine = opposite / hypothenus
Cosine = adjacent/ hypothenus
Tangent = opposite/ adjacent
A. tan E
Tan E = opposite/ adjacent
Tan E = 2 / 7.75
Tan E = 0.2580
B. Sin G = opposite / hypothenus
Sin G = 7.75 / 8
Sin G = 0.9687
C. Sec G = 1 / cos G
Cos G = adjacent / hypothenus
Sec G = 1 / (adjacent / hypothenus)
Sec G = hypothenus/ adjacent
Sec G = 8 / 2
Sec G = 4
Hello from MrBillDoesMath!
Answer:
Choice A
Discussion:
Consider the point (x,y). When reflected about the x axis the coordinate of the reflected point does NOT change but the original y values become -y in the reflection (the reflection is the same y distance below the x axis as the original y value was above the x axis)
Thank you,
MrB