Answer :
- Carbonyl group : It is a functional group composed of a carbon atom that double bonded to oxygen atom. It is represented as

Carboxylic group : It is the class of organic compound in which the carboxylic (-COOH) group is attached to a hydrocarbon is known as carboxylic.
The general formula of carboxylic is,
. According to the IUPAC naming, the carboxylic are named as alkanoic acids.
Aldehyde group : It is the class of organic compound in which the (-CHO) group is attached to a hydrocarbon is known as aldehyde.
The general representation of aldehyde is,
. According to the IUPAC naming, the aldehyde are named as alkanals.
Ketone group : It is the class of organic compound in which the (-CO) group is directly attached to the two alkyl group of carbon is known as ketone.
The general representation of ketone is,
. According to the IUPAC naming, the ketone are named as alkanone.
Ester group : It is the class of organic compound in which the (-COO) group is directly attached to the two alkyl group of carbon is known as ester.
The general representation of ester is,
. According to the IUPAC naming, the ester are named as alkyl alkanoate.
Answer:
Boiling point of solution is
Explanation:
Cane sugar is a non-volatile solute.
According to Raoult's law for a non-volatile solute dissolved in a solution-

Where,
is elivation in boiling point of solution,
is ebbulioscopic constant of solvent (how much temperature is raised for dissolution of 1 mol of non-volatile solute) and m is molality of solution.
Here, 
610 g of cane sugar =
moles of cane sugar
= 1.78 moles of cane sugar
So, molality of solution (m) = 
Plug in all the values in the above equation, we get-

So, boiling point of solution =
The binding energy of the electrons (also known as the work function of the surface) is determined as 2.43 x 10⁻¹⁹ J.
<h3>Binding energy of the electrons</h3>
The binding energy of the electrons is also known as work function of the metal and it is calculated as follows;
Ф = E - K.E
where;
Ф = hf - 86.2 kJ/mol
Ф = hc/λ - 86.2 kJ/mol
Ф = (6.63 x 10⁻³⁴ x 3 x 10⁸ )/515 x 10⁻⁹ - 86.2 kJ/mol
Ф = 3.86 x 10⁻¹⁹ J - (86200 J/mol)/(6.02 x 10²³)
Ф = 3.86 x 10⁻¹⁹ J - 1.43 x 10⁻¹⁹ J
Ф = 2.43 x 10⁻¹⁹ J
Learn more about work function here: brainly.com/question/19427469
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