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suter [353]
3 years ago
10

2no2(g)⇌n2o4(g) kp=6.7at298k a 2.35-l container contains 0.053 mol of no2 and 0.084 mol of n2o4at298k. is the reaction at equili

brium? if not, in what direction will the reaction proceed?
Chemistry
1 answer:
Mice21 [21]3 years ago
5 0
From the balanced equation of the reaction:
2NO2(g)↔ N2O4(g) 
So we just get the Kc by using the concentration of NO2 & N2O4 and compare it with the KP value which is given.
Kc = [N2O4] / [NO2]^2
Kc = 0.084 m / 0.053^2
     = 30 
by comparing Kc and Kp value and we see that Kc >Kp
So the reaction will go leftward to the direction of the reactants to increase the reactants and decrease the concentration of the products until achieving the equilibrium again.
as the reaction will be at equilibrium when Kc= Kp


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. What is a carbonyl group? Draw the carbonyl groups that are characteristic of aldehydes, ketones, carboxylic acids, and esters
Elan Coil [88]

Answer :

  • Carbonyl group : It is a functional group composed of a carbon atom that double bonded to oxygen atom. It is represented as C=O

Carboxylic group : It is the class of organic compound in which the carboxylic (-COOH) group is attached to a hydrocarbon is known as carboxylic.

The general formula of carboxylic is, C_nH_{2n+1}COOH. According to the IUPAC naming, the carboxylic are named as alkanoic acids.

Aldehyde group : It is the class of organic compound in which the (-CHO) group is attached to a hydrocarbon is known as aldehyde.

The general representation of aldehyde is, R-CHO. According to the IUPAC naming, the aldehyde are named as alkanals.

Ketone group : It is the class of organic compound in which the (-CO) group is directly attached to the two alkyl group of carbon is known as ketone.

The general representation of ketone is, R-CO-R^'. According to the IUPAC naming, the ketone are named as alkanone.

Ester group : It is the class of organic compound in which the (-COO) group is directly attached to the two alkyl group of carbon is known as ester.

The general representation of ester is, R-COO-R^'. According to the IUPAC naming, the ester are named as alkyl alkanoate.

6 0
3 years ago
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xxMikexx [17]

Answer:

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6 0
3 years ago
What is the boiling point of a solution produced by adding 610 g of cane sugar (molar mass 342.3 g/mol) to 1.4 kg of water? For
wel

Answer:

Boiling point of solution is 100.65^{0}\textrm{C}

Explanation:

Cane sugar is a non-volatile solute.

According to Raoult's law for a non-volatile solute dissolved in a solution-

                              \Delta T_{b}=K_{b}.m

Where, \Delta T_{b} is elivation in boiling point of solution, K_{b} is ebbulioscopic constant of solvent (how much temperature is raised for dissolution of 1 mol of non-volatile solute) and m is molality of solution.

Here, K_{b}=0.51^{0}\textrm{C}.kg.mol^{-1}

610 g of cane sugar = \frac{610}{342.3} moles of cane sugar

                                  = 1.78 moles of cane sugar

So, molality of solution (m) = \frac{1.78}{1.4}mol.kg^{-1}=1.27mol.kg^{-1}

Plug in all the values in the above equation, we get-

\Delta T_{b}=0.51^{0}\textrm{C}.kg.mol^{-1}\times 1.27mol.kg^{-1}=0.65^{0}\textrm{C}

So, boiling point of solution = (100+0.65)^{0}\textrm{C}=100.65^{0}\textrm{C}              

7 0
3 years ago
If light with a wavelength of 515 nm is shown on a metal surface, and photoelectrons (electrons ejected from the surface) have a
Debora [2.8K]

The binding energy of the electrons (also known as the work function of the surface) is determined as 2.43 x 10⁻¹⁹ J.

<h3>Binding energy of the electrons</h3>

The binding energy of the electrons is also known as work function of the metal and it is calculated as follows;

Ф = E - K.E

where;

Ф = hf - 86.2 kJ/mol

Ф = hc/λ - 86.2 kJ/mol

Ф = (6.63 x 10⁻³⁴ x 3 x 10⁸ )/515 x 10⁻⁹   -  86.2 kJ/mol

Ф = 3.86 x 10⁻¹⁹ J - (86200 J/mol)/(6.02 x 10²³)

Ф = 3.86 x 10⁻¹⁹ J - 1.43  x 10⁻¹⁹ J

Ф = 2.43 x 10⁻¹⁹ J

Learn more about work function here: brainly.com/question/19427469

#SPJ1

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