Answer:
1.01atm is the pressure of the gas
Explanation:
The difference in heights in the two sides is because of the difference in pressure of the enclosed gas and the atmospheric pressure. This difference is in mm of the nonvolatile liquid. The difference in mm Hg is:
32.3mm * (0.993g/mL / 13.6g/mL) = 2.36mmHg
As atmospheric pressure is 765mm Hg and assuming the gas has more pressure than the atmospheric pressure (There is no illustration), the pressure of the gas is:
765mm Hg + 2.36mm Hg = 767.36 mmHg
In atm:
767.36 mmHg * (1atm / 760 mmHg) =
1.01atm is the pressure of the gas
20.7 Degree celsius is the temperature of Zippy's room.
Explanation:
The initial conditions of the kookie cola will be depicted by P1,V1 and T1.
P1= 36.5 psi or 2.4816 atm
V1= 355ml or 0.35 L
T1= 275.5K
The final conditions are given P2,V2 and T2
P2= 38.9 psi or 2.6469 atm
V2 = 355 ml or 0.35 L
also the solubility of the carbon dioxide does not change with temperature.
Applying the formula
P1VI/T1=P2V2/T2
since volume does not change and remains constant.
It can be written as:
P1/T1=P2/T2
= 2.4816/275.5=2.6469/T2
T2= 293.85 K
Answer:
Striped should be the answer
Answer:
Explanation:
count given by old sample = .97 disintegrations per minute per gram
count given by fresh sample = 6.68 disintegrations per minute per gram
Half life of radioactive carbon = 5568 years
rate of disintegration
dN / dt = λ N
In other words rate of disintegration is proportional to no of radioactive atoms present . As number reduces rate also reduces .
Let initial no of radioactive be N₀ and after time t , number reduces to N
N₀ / N = 6.68 / .97
Now
λ is disintegration constant
λ = .693 / half life
= .693 / 5568
= .00012446 year⁻¹
Putting the values in the equation above
1.929577 = .00012446 t
t = 15503.6 years .
Answer:
The electronegativity of carbon (EN = 2.55) is too small to allow carbon to form C4- ions with most metals and too large for carbon to form C4+ ions when it reacts with nonmetals. Carbon therefore forms covalent bonds with many other elements.
