We are given that if equally sized central angles, each with a measure of n°, are drawn, the number of sectors that are formed will be equal to $\frac{360^{\circ}}{n^{\circ}}$

So, Number of sectors = $\frac{360^{\circ}}{n^{\circ}}$

The arc length of each sector is the circumference divided by the number of sectors

$\Rightarrow \frac{\pi \cdot d}{\frac{360^{\circ}}{n^{\circ}}}$

Diameter d = 2r (r = radius)

$\Rightarrow \frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}}$

Option b is true

Hence $\frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}}$ best completes this argument

7 0

3 years ago

Forty-four students go on a field trip. The students are divided into groups of 7 students. How many groups of 7 will there be?.

strojnjashka [21]

To solve this problem, you need to divide the total number of students going on the field trips with the number of students in each group.

44/7

= 6 R 2

Since, I assume there can <em>only</em> be groups of 7, the answer is 6.

4 0

2 years ago