Determine the area, in square feet, of the smallest square that can contain a circle with a radius of 8 feet.

POINTS!! I NEED HELP WITH THIS, WILL GIVE BRAINLIEST TO BEST ANSWER

neonofarm [45]

Answer:

Conjecture

Disjunction

Counterexample

Conjunction

Inductive reasoning

Conditional

Step-by-step explanation:

I used Quizlet and I knew most of them.

5 0

3 years ago

Read 2 more answers

Consider the differential equation x2y′′ − 9xy′ + 24y = 0; x4, x6, (0, [infinity]). Verify that the given functions form a funda

pantera1 [17]

Answer:

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

$y= c_1x^4+c_2x^6$

Step-by-step explanation:

Given equation is

$x^2y'' - 9xy+24y=0$

This Euler Cauchy type differential equation.

So, we can let

$y=x^m$

Differentiate with respect to x

$y'= mx^{m-1}$

Again differentiate with respect to x

$y''= m(m-1)x^{m-2}$

Putting the value of y, y' and y'' in the differential equation

$x^2m(m-1) x^{m-2} - 9 x m x^{m-1}+24x^m=0$

$\Rightarrow m(m-1)x^m-9mx^m+24x^m=0$

$\Rightarrow m^2-m-9m+24=0$

⇒m²-10m +24=0

⇒m²-6m -4m+24=0

⇒m(m-6)-4(m-6)=0

⇒(m-6)(m-4)=0

⇒m = 6,4

Therefore the auxiliary equation has two distinct and unequal root.

The general solution of this equation is

$y_1(x)=x^4$

and

$y_2(x)=x^6$

First we compute the Wronskian

$W(x)= \left|\begin{array}{cc}y_1(x)&y_2(x)\\y'_1(x)&y'_2(x)\end{array}\right|$

$= \left|\begin{array}{cc}x^4&x^6\\4x^3&6x^5\end{array}\right|$

=x⁴×6x⁵- x⁶×4x³

=6x⁹-4x⁹

=2x⁹

≠0

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

$y= c_1x^4+c_2x^6$

5 0

3 years ago

Find all values of x in the interval [0, 2π] that satisfy the equation. 3 sin(2x) = 3 cos(x)

natita [175]

3 sin ( 2 x ) = 3 cos x
3 · 2 sin x cos x - 3 cos x = 0
6 sin x cos x - 3 cos x = 0 /: 3
2 sin x cos x - cos x = 0
cos x ( 2 sin x - 1 )
cos x = 0,
x 1 = π/2, x 2 = 3π/2;
2 sin x - 1 = 0
2 sin x = 1
sin x = 1/2
x 3 = π/6, x 4 = 5π/6.

7 0

3 years ago

Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about the

m_a_m_a [10]

Answer:

Required volume is $\frac{4864\pi}{3}$ unit.

Step-by-step explanation:

Given equations of curves,

$y=32-x^2$ , $y=x^2$

substitute second in first we will get,

$x^2=36-x^2\implies x^2=16\implies x=\pm 4$

When $x=4, y=16$ and $x=-4, y=16$ . Thus both curves intersect at the points (4,16),(-4,16). And thus $-4$ .

Considering width of the representative rectangle as $\Delta x$ which is parallel to x-axis because of considering cylindrical shell. Therefore volume of the shell is given by,