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3 years ago

11

a fountain in a pond has a pump that recirculates 75 gallons of water in 1/4 of an hour.express this rate as a unit rate in gall

ons per hour

1 answer:

olga55 [171]3 years ago

6 0

So if in 1/4 of an hour 75 gallons are pumped you would multiply 75 by four which will give you 300. This means 300 gallons are pumped in an hour

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Calculate AC<br> Round to the nearest tenth.

Free_Kalibri [48]

Answer:

3,266.53

Step-by-step explanation:

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2 years ago

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Brad and Tom are comparing their classes scores on a math test . Both of their classes had mean scores of 80 on the test, but Br

timama [110]

Answer:

Brad´s class has the lowest score

Step-by-step explanation:

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2 years ago

Translate and solve: Three more than the difference of 6s and 5s is equal to the difference of 1/12 and 1/6

PilotLPTM [1.2K]

Answer:

a. $(6s-5s)+3=\frac{1}{12}-\frac{1}{6}$

b. $s=-\frac{37}{12}$

Step-by-step explanation:

You need to remember that:

1. The word "more" indicates Addition.

2. The "Difference" is the result of a Subtraction.

a. Then, knowing this information, you know that:

- "The difference of $6s$ and $5s$ " must be expressed as:

$6s-5s$

- Then, "Three more than the difference of $6s$ and $5s$ " is:

$(6s-5s)+3$

- "The difference of $\frac{1}{12}$ and $\frac{1}{6}$ " can be expressed in this form:

$\frac{1}{12}-\frac{1}{6}$

Therefore, "Three more than the difference of $6s$ and $5s$ is equal to the difference of $\frac{1}{12}$ and $\frac{1}{6}$ " is:

$(6s-5s)+3=\frac{1}{12}-\frac{1}{6}$

b. Solve for "s" in order to find its value:

$s+3=-\frac{1}{12}\\\\12(s+3)=-1\\\\12s+36=-1\\\\12s=-1-36\\\\s=-\frac{37}{12}$

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3 years ago

20. A ball is dropped from a height of a little over 5 feet, and the height is measured at small intervals. The table below show

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Step 1:

a) Write the quadratic model

a = -15.64

b = -1.24

c = 5.23

$P(t)=-15.64t^2\text{ - 1.24t + 5.2}3$

b) t = 0.30

$\begin{gathered} P(t)=-15.64t^2\text{ - 1.24t + 5.2}3 \\ =\text{ -15.64 }\times0.3^2\text{ - 1.24}\times\text{ 0.3 + 5.2}3 \\ =\text{ -1.4076 - 0.372 + }5.23 \\ =\text{ 3.45} \end{gathered}$

c) t = 0.52 seconds

$\begin{gathered} p(t)=-15.64t^2\text{ - 1.23t + 5.23} \\ =\text{ -15.64}\times0.52^2\text{ - 1.23}\times0.52\text{ + 5.23} \\ =\text{ -4.23 - 0.64 + 5.23} \\ =\text{ 0.36} \end{gathered}$

d) 0.30 is more likely to be relaible.

e)

$\begin{gathered} p(t)\text{ = 1} \\ p(t)=-15.64t^2\text{ - 1.23t + 5.23} \\ 1=-15.64t^2\text{ - 1.23t + 5.23} \\ -15.64t^2\text{ - 1.23t + 4.23 = 0} \\ t\text{ = 0.48222} \\ \text{t = 0.48 seconds} \end{gathered}$

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1 year ago

Find two numbers whose difference is 154 and whose product is a minimum.

Serggg [28]

Y - x = 154
let z = xy = x(154 + x) = x^2 + 154x

we need to find the minimum value of z

z' = 2x + 154 which = zero for minm or maxm value

x = -77 and y = 154 -77 = 77

so the 2 numbers are -77 and 77

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3 years ago