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2 years ago

7

PLS HELP ASAP WILL DO ANYTHING The picture below shows a right-triangle-shaped charging stand for a gaming system: Which express

ion shows the length of side AB? (6 points) 8 cosec 60° 8 divided by sin 60 degrees 8 divided by cos 60 degrees 8 tan 60°

1 answer:

Fynjy0 [20]2 years ago

7 0

Answer:

AB= 8/Cosine 60 degrees

Step-by-step explanation:

Cosine=Adjacent/Hypotenuse

Cosine=8/AB

AB=8/Cosine 60 degrees

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The doubling period of a bacterial population is 15 minutes. At time t= 80 minutes, the bacterial population was 90000

Papessa [141]

Answer:

here i finished!

hope it helps yw!

Step-by-step explanation:

The doubling period of a bacterial population is 15 minutes.

At time t = 90 minutes, the bacterial population was 50000.

Round your answers to at least 1 decimal place.

:

We can use the formula:

A = Ao*2^(t/d); where:

A = amt after t time

Ao = initial amt (t=0)

t = time period in question

d = doubling time of substance

In our problem

d = 15 min

t = 90 min

A = 50000

What was the initial population at time t = 0

Ao * 2^(90/15) = 50000

Ao * 2^6 = 50000

We know 2^6 = 64

64(Ao) = 50000

Ao = 50000/64

Ao = 781.25 is the initial population

:

Find the size of the bacterial population after 4 hours

Change 4 hr to 240 min

A = 781.25 * 2^(240/15

A = 781.25 * 2^16

A= 781.25 * 65536

A = 51,199,218.75 after 4 hrs

6 0

2 years ago

Graph the function y = x3 + x2 – 6x + 5. What are the coordinates, to the nearest tenth, of the relative maximum of the graph? (

Debora [2.8K]

Answer:A

Step-by-step explanation:edge

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2 years ago

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The daily revenues of a cafe near the university are approximately normally distributed. The owner recently collected a random s

lbvjy [14]

Answer:

The sample size to obtain the desired margin of error is 160.

Step-by-step explanation:

The Margin of Error is given as

$MOE=z_{crit}\times\dfrac{\sigma}{\sqrt{n}}$

Rearranging this equation in terms of n gives

$n=\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2$

Now the Margin of Error is reduced by 2 so the new M_2 is given as M/2 so the value of n_2 is calculated as

$n_2=\left[z_{crit}\times \dfrac{\sigma}{M_2}\right]^2\\n_2=\left[z_{crit}\times \dfrac{\sigma}{M/2}\right]^2\\n_2=\left[z_{crit}\times \dfrac{2\sigma}{M}\right]^2\\n_2=2^2\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2\\n_2=4\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2\\n_2=4n$

As n is given as 40 so the new sample size is given as

$n_2=4n\\n_2=4*40\\n_2=160$

So the sample size to obtain the desired margin of error is 160.

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3 years ago

Solve the quadratic equation.<br>m^2/15 -3 = 2

Radda [10]

The answer is $5 \sqrt{3}$

<h3>Explanation :</h3>

$\frac{ {m}^{2} }{15} - 3 = 2$

$\frac{ {m}^{2} }{15} = 2 + 3$

$\frac{ {m}^{2} }{15} = 5$

${m}^{2} = 5 \times 15$

${m}^{2} = 75$

$m = \sqrt{75}$

$m = \sqrt{25 \times 3}$

$m = \sqrt{25} \times \sqrt{3}$

$m = 5 \sqrt{3}$

CMIIW

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2 years ago

Suppose a solitaire player has played 1000 games. Predict how many times the play turned over a red card as the first card

olga nikolaevna [1]

About 500 times since there is a 50/50 chance

i think that is right

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3 years ago

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