Ask question

Ask question

All categories

evablogger [386]

3 years ago

8

Please help. I don't understand it. HELP ASAP....

1 answer:

Vladimir [108]3 years ago

5 0

Answer:

$\large\boxed{x\leq-27}$

Step-by-step explanation:

$\dfrac{x}{-9}\geq3\qquad\text{change the signs}\\\\\dfrac{x}{9}\leq-3\qquad\text{multiply both sides by 9}\\\\9\!\!\!\!\diagup^1\cdot\dfrac{x}{9\!\!\!\!\diagup_1}\leq(-3)(9)\\\\x\leq-27$

You might be interested in

In Europe, the speed limits on the highways are posted in kilometers per hour. In the United States, the speed limits are posted

mina [271]

I believe the answer is 104 km per hour. correct me if i’m wrong anyone.

8 0

3 years ago

Why is 6/11=x/33 not a proportion

sertanlavr [38]

6/11=x/33 is not a proportion because they aren't equal to each other.

6 0

3 years ago

Karen is 6 years older than her sister Michelle, and Michelle is 2 years younger than their brother David. If the sum of their a

ale4655 [162]

$K\ \rightarrow\ the\ Karen's\ age\\M\ \rightarrow\ the\ Michelles\ age \\D\ \rightarrow\ the\ David's\ age\\\\K=M+6\\M=D-2\ \ \ \Rightarrow\ \ \ D=M+2\\K+M+D=62\\\\(M+6)+M+(M+2)=62\\3M+8=62\\3M=54\ /:3\\M=18\ \ \ \Rightarrow\ \ \ K=18+6=24\ \ \ and\ \ \ D=18+2=20\\\\Ans.\ Michelle\ is\ 18,\ David\ is\ 20,\ Karen\ is\ 24.$

6 0

3 years ago

An air plane moves at a constant speed of 120 miles per hour for 3 hours. How far does it go?

Anvisha [2.4K]

Answer: 360

Step-by-step explanation: All you got to do is multiply 120 by 3

7 0

3 years ago

Read 2 more answers

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago