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earnstyle [38]
3 years ago
6

Which expression is equivalent to (2x-5)-5x(x-4)

Mathematics
1 answer:
Murrr4er [49]3 years ago
7 0
2x-5-5x²+20x
-5x+22x-5
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Last year Billy weighed 75kg. This year he weighed 90kg. With what percentage did his weight increase. SHOW ALL WORK!!!
polet [3.4K]

well let's round. 90= 100, 75=80 that is how I face it. now 80 is 1/5 of 5/5= 100. so as a (%) we would sort it like:::: it is 80% out of +100 so he must have grown around 13%-16% due to him being 75kg in the past.

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3 years ago
Angles α and β are the two acute angles in a right triangle. Use the relationship between sine and cosine to find the value of β
Dimas [21]

Answer:

From given relation the value of β is 37.5°

Step-by-step explanation:

Given as :

α and β are two acute angles of right triangle

Acute angle have measure less than 90°

Now given as :

sin(\frac{x}{2} + 2x) = cos(2x +\frac{3x}{2})

Or, cos(90° - (\frac{x}{2}+2x)) =  cos(2x +\frac{3x}{2})

SO, (90° - (\frac{x}{2}+2x)) = 2x+\frac{3x}{2}

Or, 90° =  2x+\frac{3x}{2} + \frac{x}{2}+2x

or, 90° = \frac{4x}{2} + 4x

Or,  90° =  \frac{12x}{2}

So, x =  \frac{90}{6} = 15°

∴ sin(\frac{x}{2} + 2x) = sin(\frac{15}{2} + 30)

So, sin(\frac{x}{2} + 2x) = sin\frac{75}{2}

∴  The value of Ф_1 = \frac{75}{2} = 37.5°

Similarly  cos(2x +\frac{3x}{2}) =  cos(30 +\frac{45}{2})

So ,The value of Ф_2 = \frac{105}{2} = 52.5°

∵ β   α

So, As 37.5°52.5°

∴ β = 37.5°

Hence From given relation the value of β is 37.5°  Answer

7 0
3 years ago
Which expression can be used to find 25 percent of 88?
Dominik [7]

Answer: 25/100* 88

Step-by-step explanation:

6 0
2 years ago
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Find the area of a rectangle with a length of (8m³)² and a width of (4x²m⁴)
Alisiya [41]

Answer:nhnc

add it mc

Step-by-step explanation:vgnhc

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2 years ago
Which of the following shows the best way to set up the product of (2x - 5) and<br> (4 - 3x + 4.)?
masha68 [24]

Answer:

  C

Step-by-step explanation:

It usually works best to use the polynomial with fewer terms as the multiplier. A row of partial products is written for each term of the multiplier, so the fewer terms will result in fewer rows of partial products.

In order to keep like terms together, it is preferable to allocate a separate column of the multiplication tableau to each power of the operands or product. This means we want to make note of the fact that the cubic multiplicand has a coefficient of 0 for its x^2 term.

The best setup is the one shown in the attachment.

3 0
2 years ago
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