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oksian1 [2.3K]
3 years ago
6

Can some one help me plz??

Mathematics
1 answer:
Hitman42 [59]3 years ago
5 0
The answer is C for this question
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Suppose Felipe has 9.24 pounds of seed if it takes 6.6 pounds of seed to plant on acre of grass how many acres of grass can be p
Lyrx [107]

Answer:

1.4 acres of grass can be planted.

Step-by-step explanation:

He has 9.24 pounds of seeds.

If one acre of grass needs 6.6 pounds of seeds we can divide 9.24 pounds by 6.6 pounds to find how many acres of grass he can plant.

9.24 lbs × \frac{1acre}{6.6 lbs} = 1.4 acres

4 0
3 years ago
Multiply. x + 4x + 2 2x2 + 3x – 4​
Yuliya22 [10]

Answer:

I think question is:

(x+4x+2)(2x^2+3x-4)

:(5x+2)(2x^2+3x-4)

5x(2x^2+3x-4)+2(2x^2+3x-4)

10x^3+15x^2-20x+4x^2+6x-8

10x^3+19x^2-14x-8

7 0
3 years ago
Which is correct classification for the triangle (A) obtuse (B) acute (C)right (D) equiangular
nexus9112 [7]

Answer:

c) Right

Step-by-step explanation:

An Right triangle is a triangle with an angles being 90 degrees and we know that 2 of the angles are 59 and 31 and we know that the sum of all the angles in a triangle will equal 180 so 180-59-31 = 90 so this triangle has a 90 degree angle making it a right triangle

4 0
3 years ago
The diagram shows the net of a square pyramid.
fenix001 [56]

Answer:

Given,

Base (b) = 16 cm

slant Height (h) = 15 cm

a= 8 cm {a is the half of base}

x = ?

Using Pythagoras Theorem

<em><u>p</u></em><em><u>^</u></em><em><u>2</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>h^</u></em><em><u>2</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>b^</u></em><em><u>2</u></em>

x^2= 15 - 8

x^2 = 7

x = 2.64 cm

4 0
3 years ago
ONLY ANSWER NO WORK WILL MARK BRAINLIEST
Whitepunk [10]
Alright, here goes:
For this question, you are asked about the median and Interquartile Range(IQR), so first you need to understand what that means.
The IQR is the box in the middle of the box-and-whisker-plot. The question asks for the place to have a small IQR, so the most likely places are Pensacola and Jacksonville.
The question is also asking for a high median temperature. The median is the line in the middle of the plot.
The median of Pensacola's plot is higher than the median of Jacksonville, so Pensacola Beach is your answer :)
5 0
3 years ago
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