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o-na [289]
3 years ago
15

Find all the zeroes of the equation. Show all your work. -3x^4+27x^2+1200=0

Mathematics
1 answer:
madam [21]3 years ago
4 0

There are two things you should do right away

Divide through by minus 3

Substitute another letter (say z) for x^2

Step One

-3x^4/-3 +27x^2/-3 + 1200/-3 = 0/-3

x^4 - 9x^2 - 400 = 0

Step 2

Let z = x^2

(x^2)^2 - 9(x^2) - 400 = 0

z^2 - 9z^2 - 400 = 0

Step 3

By factoring solve for z

(z - 25)(z + 16) = 0

z = 25

x^2 = 25

x =  +/- 5

============

z + 16 = 0

z = - 16

x^2 = - 16

x = sqrt(-16)

x = +/- 4i

I've included a graph to show that the zeros are correct.

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The rectangle below has an area of zº +82 + 15 square meters and a width of 2 + 3 meters.
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Answer:

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Step-by-step explanation:

From the question given above, the following data were obtained:

Area (A) = (x² + 8x + 15) m²

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Length (L) =?

The lenght of the rectangle can be obtained as follow:

A = L × W

x² + 8x + 15 = L (x + 3)

Divide both side by x + 3

L = x² + 8x + 15 / x + 3

L = (x + 5) m

Please attached photo for explanation.

Therefore, the length of the rectangle is: (x + 5) m

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