It’s C! that’s the answer, hope it helps
Very simple.
Let's say you have an equation.
f(x) = x^2
You are asked to find the value for y when x equals 1.
The new equation is: f(1) = (1)^2
f(1) = 1
When x = 1, y = 1.
The same concept is applied here.
In the graph, where does x equal 0?
It equals zero at the origin.
Is there any y-value associated with 0?
Yes, there is.
Y equals five when x equals 0.
So
h(0) = 5
See the attached picture:
The transformation of A is A' = (8, -3)
<h3>How to determine the transformation?</h3>
From the graph, we have:
A = (3,1)
The scale factor and the center of dilation are given as:
k = 2
(a,b) = (-2,1)
The rule of reflection across the axis is:
(x,y) ⇒ (x,-y)
So, we have:
A' = (3,-1)
The rule of dilation is represented as:
(x,y) ⇒ (k(x - a) + a, k(y - b) + b)
So, we have:
A' = (2(3 + 2) - 2, 2(-1 - 1) + 1)
Evaluate
A' = (8, -3)
Hence, the transformation of A is A' = (8, -3)
Read more about transformation at:
brainly.com/question/4289712
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