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3 years ago

What would the circumference be of a circle if the radius is 3 units

1 answer:

7 0

If we have a circle with a radius of 3 we need to find the diameter of the circle. Remember radius is half of the diameter. So, the diameter is 6 units.

Use the circumference formula: C=3.14D

C=3.14(6)

C=18.84 units

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Perform the indicated operations. Write the answer in standard form, a+bi. -4 + 4i / -3-6i

vesna_86 [32]

Answer:

$\frac{ - 4 + 4i}{ - 3 - 6i} \\ \frac{ - 4 + 4i}{ - 3 - 6i} \times \frac{ - 3 + 6i}{ - 3 + 6i} \\ = \frac{12 - 24i - 12i + 24 {i}^{2} }{ {( - 3)}^{2} - {(6i)}^{2} } \\ = \frac{ - 12 - 36i}{45} \\ = \frac{ - 12}{45} \frac{ - 36i}{45} \\ than \: you$

5 0

3 years ago

What’s is the answer to this problem

katrin2010 [14]

Recall that the sum of all 3 angles of a triangle is 180. So,
82 + 45 + x = 180>> 127 + x = 180
>> x = 180 - 127
>> x = 53 (final answer)

7 0

3 years ago

If the area of a park is exactly halfway between 2.4 and 2.5 acres, what is the area of the park? Explain. Please if you know th

grandymaker [24]

"If the area of a park is exactly halfway between 2.4 and 2.5 acres, what is the area of the park" its 2.45 acres.

8 0

3 years ago

Solve for x: 5x - 3y = 22 10x - 4y = 46

Alik [6]

Answer:

x=5, y=1

Step-by-step explanation:

Isolate x for 5x-3y=22

5x-3y=22

Add 3y to both sides

5x-3y+3y=22+3y

Simplify

5x=22+3y

Divide both sides by 5

5x/5=22/5+3y/5

Simplify

x=22+3y/5

Substitute x=22+3y/5

10*22+3y/5-4y=46

Simplify 10*22+3y/5-4y

10*22+3y/5=2(3y+22)

=2(3y+22)-4y

Expand 2(3y+22)

=6y+44-4y

Simplify 6y+44-4y

=2y+44

Isolate y for 2y+44=46

2y+44=46

Subtract 44 from both sides:

2y+44-44=46-44

Simplify

2y=2

Divide both sides by 2;

2y/2=2/2

Simplify;

y=1

For x=22+3*1/5 substitute y=1

y=22+3*1/5

22+3*1=25

=25/5

Divide the numbers;25/5=5

x=5

The solutions to the system of equations are;

x=5, y=1

8 0

3 years ago

Question 2 (2 points)

hoa [83]

Answer:

4) The limit does not exist.

General Formulas and Concepts:

Calculus

Limits

Right-Side Limit: $\displaystyle \lim_{x \to c^+} f(x)$
Left-Side Limit: $\displaystyle \lim_{x \to c^-} f(x)$

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Step-by-step explanation:

*Note:

For a limit to exist, the right-side and left-side limits must be equal to each other.

Step 1: Define

Identify

$\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x ,\ x < 5\\8 ,\ x = 5\\x + 3 ,\ x > 5\end{array}$

Step 2: Find Left-Side Limit

Substitute in function [Left-Side Limit]: $\displaystyle \lim_{x \to 5^-} 5 - x$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^-} 5 - x = 5- 5 = 0$

Step 2: Find Left-Side Limit

Substitute in function [Right-Side Limit]: $\displaystyle \lim_{x \to 5^+} x + 3$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8$

∴ since $\displaystyle \lim_{x \to c^+} f(x) \neq \lim_{x \to c^-} f(x)$ , $\displaystyle \lim_{x \to 5} f(x) = \text{DNE}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

5 0

3 years ago