The target pulse rate during moderate-intensity activity for a person who is 21 years old is 144.46
<h3>Determine the equation of the regression line</h3>
The table of values is given as:
Age (years) 20 30 40 50 60 70
Target Heart Rate 150 133 126 119 112 105
(beats per minute)
To determine the equation of the regression line, we enter the above values in a graphing calculator.
From the graphing calculator, we have the following summary:
- Sum of X = 270
- Sum of Y = 745
- Mean X = 45
- Mean Y = 124.1667
- Sum of squares (SSX) = 1750
- Sum of products (SP) = -1475
The regression equation is
y = bx + a
Where b represents the slope and a represents the y-intercept
So, we have:
b = SP/SSX = -1475/1750 = -0.84
a = MY - bMX = 124.17 - (-0.84*45) = 162.10
So, we have:
y = -0.84x + 162.10
Hence, the equation of the regression line is y = -0.84x + 162.10
<h3>The slope of the
regression line and the
interpretation </h3>
In (a), we have:
Slope, b = -0.84
This means that the slope of the regression line is -0.84 and the interpretation is the target heart beat decreases by 0.84 per year
<h3>The dependent variable axis intercept and the
interpretation </h3>
The dependent variable is y.
In (a), we have:
Y-intercept, a = 162.10
This means that the dependent variable axis intercept of the regression line is 162.10 and the interpretation is the initial target heart beat is 162.10
<h3>The target pulse rate during moderate-intensity activity for a person who is 21 years old</h3>
This means that
x = 21
So, we have:
y = -0.84 * 21 + 162.10
Evaluate
y = 144.46
Hence, the target pulse rate during moderate-intensity activity for a person who is 21 years old is 144.46
Read more about linear regression at:
brainly.com/question/25987747
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