2 years ago

Please help me I don’t understand what I’m supposed to do ! Unit 1 - Triangle Congruence

Mathematics

1 answer:

Luba_88 [7]2 years ago

6 0

Answer:

i dont either

Step-by-step explanation:

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2^4n × 2^ 2n = 512<br> What is the value of n.

Marina86 [1]

Step-by-step explanation:

${2}^{4n} \times {2}^{2n} = 512$

${2}^{4n} \times {2}^{2n} = {2}^{9}$

${2}^{4n + 2n} = {2}^{9}$

$6n = 9$

$n = \frac{3}{2}$

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2 years ago

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43, 52, 56, 47, 53, 60, 45, 40, 52, 48, 50<br> Find the median and mode of the following data.

Molodets [167]

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median = 50

mode = 52

Step-by-step explanation:

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Consider the following set of data which is plotted on the scatter diagram below

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Step-by-step explanation:

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2 years ago

Consider th following formula used to find a cone v= 3.14r^2 h/3

lys-0071 [83]

Here's the volume formula (and the area formula) typed a little neater than that.
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2 years ago

Using these complex zeros (1,1,-1/2,2+i,2-i) factor f(x)=-2x^5 +11x^4 -22x^3 +14x^2 +4x -5

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$\bf \begin{cases}
x=1\implies &x-1=0\\
x=1\implies &x-1=0\\
x=-\frac{1}{2}\implies 2x=-1\implies &2x+1=0\\
x=2+i\implies &x-2-i=0\\
x=2-i\implies &x-2+i=0
\end{cases}
\\\\\\
(x-1)(x-1)(2x+1)(x-2-i)(x-2+i)=\stackrel{original~polynomial}{0}
\\\\\\
(x-1)^2(2x+1)~\stackrel{\textit{difference of squares}}{[(x-2)-(i)][(x-2)+(i)]}$

$\bf (x^2-2x+1)(2x+1)~[(x-2)^2-(i)^2]
\\\\\\
(x^2-2x+1)(2x+1)~[(x^2-4x+4)-(-1)]
\\\\\\
(x^2-2x+1)(2x+1)~[(x^2-4x+4)+1]
\\\\\\
(x^2-2x+1)(2x+1)~[x^2-4x+5]
\\\\\\
(x^2-2x+1)(2x+1)(x^2-4x+5)$

of course, you can always use (x-1)(x-1)(2x+1)(x²-4x+5) as well.

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3 years ago