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Stolb23 [73]
3 years ago
10

What is r squared+7r+6=0

Mathematics
1 answer:
Firlakuza [10]3 years ago
7 0

Answer:

r = -6, -1

Step-by-step explanation:

r^2 + 7r+6 =0

Factor

What 2 numbers multiply to 6 and add to 7

6*1 =6

6+1 =7

(r+6) (r+1) =0

Using the zero product property

r+6 =0        r+1 =0

r = -6            r=-1

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In a class of 6, there are 2 students who forgot their lunch.
lukranit [14]

Answer:

1/8

Step-by-step explanation:

AB,AA,BB,BB,BB,BB,BB,BB,

*A IS THE students that forgot thier lunch

4 0
3 years ago
Estefani‘s house is at point E (3,-2) and Jasmin’s house is at point J (-5,3). Jasmin’s house is the Mid-point of Estefani’s hou
iren [92.7K]

The formula for midpoint is

(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})

Look at the image below to see the line segment of Estefani's (A), Jasmin's (M), and Preston's (B) houses. Keep in mind that the segment shown below is not accurate in regards to how the line segment formed by Estefani's, Jasmin's, and Preston's houses. It is simply there so you can picture the segment better.

In this case:

x_{1} =3\\x_{2} =unknown\\y_{1} =-2\\y_{2} =unknown

^^^Plug in these number into the formula given above...

(\frac{3+x}{2}, \frac{-2 + y}{2})

To find what x is (a coordinate of Preston's house) you must take the x-value part of the midpoint equation (\frac{3+x}{2}) and set it equal to the x-value of the midpoint (-5). Then you must solve for x:

\frac{3+x}{2} = -5

3 + x = -5 * 2

3 + x = -10

x = -10 - 3

x = -13

To find what y is (a coordinate of Preston's house) you must take the  y-value part of the midpoint equation(\frac{-2 + y}{2}) and set it equal to the y-value of the midpoint (3). Then you must solve for y:

\frac{-2 + y}{2} = 3

-2 + y = 3 * 2

-2 + y = 6

y = 6 + 2

y = 8

The coordinate of Preston's house is:

(-13, 8)

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0
3 years ago
At a middle school, 30% of the
Llana [10]

Answer:

I don't understand percentages

3 0
4 years ago
If a(x) = 3x + 1 and b (x) = square root of x-4, what is the domain of (b o a)(x)
Monica [59]

( 1, ∞)  is the domain of (b o a)(x)

<h3>What is Function?</h3>

A function is defined as a relation between a set of inputs having one output each.

According to the question,

a(x) = 3x + 1 \\\\b (x) =\sqrt{x+4}

To find the domain of the composite function,

(b o x) (x) = b(a(x))\\\\(b o x) (x) = b(a(3x-1))\\\\(b o x) (x) = \sqrt{3x+ 1 -4} \\\\(b o x) (x) = \sqrt{3x -3}\\\\

Therefore,

3x - 3 \geq 0\\3x \geq 3\\x \geq 1\\\\

Hence , [ 1, ∞ ] is is the domain of (b o a)(x).

learn more about function here:brainly.com/question/12431044

#SPJ1

8 0
2 years ago
You are given the following information obtained from a random sample of 5 observations. 20 18 17 22 18 At 90% confidence, you w
Margaret [11]

Answer:

a

  The null hypothesis is  

         H_o  : \mu  =  21

The Alternative  hypothesis is  

           H_a  :  \mu<   21

b

     \sigma_{\= x} =   0.8944

c

   t = -2.236

d

  Yes the  mean population is  significantly less than 21.

Step-by-step explanation:

From the question we are given

           a set of  data  

                               20  18  17  22  18

       The confidence level is 90%

       The  sample  size  is  n =  5  

Generally the mean of the sample  is  mathematically evaluated as

        \= x  =  \frac{20 + 18 +  17 +  22 +  18}{5}

       \= x  =  19

The standard deviation is evaluated as

        \sigma =  \sqrt{ \frac{\sum (x_i - \= x)^2}{n} }

         \sigma =  \sqrt{ \frac{ ( 20- 19 )^2 + ( 18- 19 )^2 +( 17- 19 )^2 +( 22- 19 )^2 +( 18- 19 )^2 }{5} }

         \sigma = 2

Now the confidence level is given as  90 %  hence the level of significance can be evaluated as

         \alpha = 100 - 90

        \alpha = 10%

         \alpha =0.10

Now the null hypothesis is  

         H_o  : \mu  =  21

the Alternative  hypothesis is  

           H_a  :  \mu<   21

The  standard error of mean is mathematically evaluated as

         \sigma_{\= x} =   \frac{\sigma}{ \sqrt{n} }

substituting values

         \sigma_{\= x} =   \frac{2}{ \sqrt{5 } }

        \sigma_{\= x} =   0.8944

The test statistic is  evaluated as  

              t =  \frac{\= x - \mu }{ \frac{\sigma }{\sqrt{n} } }

substituting values

              t =  \frac{ 19  - 21 }{ 0.8944 }

              t = -2.236

The  critical value of the level of significance is  obtained from the critical value table for z values as  

                   z_{0.10} =  1.28

Looking at the obtained value we see that z_{0.10} is greater than the test statistics value so the null hypothesis is rejected

6 0
4 years ago
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