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n200080 [17]
3 years ago
13

Whats a method you can use for times tables?

Mathematics
2 answers:
romanna [79]3 years ago
7 0
For 5 just add 5 each time
Sholpan [36]3 years ago
4 0
For the 9 times table, in the answer section, order the answers 9,1,2,3,4,5,6,7,8,9 and then backwards order 0,1,2,3,4,5,6,7,8. This is a very easy way to understand the 9 times table.
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X^2+(5/4)x+? <br> What must be added to make a perfect square binomial
vichka [17]
25/64 is the answer to your question
5 0
3 years ago
HELP ME!!!
larisa [96]

Answer:

  -2, 8/3

Step-by-step explanation:

You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...

  A = (1/2)(f(a) +f(4))(4 -a)

  = (1/2)((3a -1) +(3·4 -1))(4 -a)

  = (1/2)(3a +10)(4 -a)

We want this area to be 12, so we can substitute that value for A and solve for "a".

  12 = (1/2)(3a +10)(4 -a)

 24 = (3a +10)(4 -a) = -3a² +2a +40

  3a² -2a -16 = 0 . . . . . . subtract the right side

  (3a -8)(a +2) = 0 . . . . . factor

Values of "a" that make these factors zero are ...

  a = 8/3, a = -2

The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.

_____

<em>Alternate solution</em>

The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.

5 0
3 years ago
Michael is making a backdrop for the school play. He bought 4 rolls of material to use. He used 27 square feet of material for t
agasfer [191]
6 square feet in each roll
7 0
3 years ago
A 20-foot ladder leaning against a wall is used for each a window that is 17 feet above the ground. How far from the wall is the
zlopas [31]
We know that the building must form a right angle with the ground, so the triangle formed by the ladder, the wall, and the distance between the base of the ladder and the wall is a right triangle. We can use the Pythagorean theorem to find the distance the ladder is from the building.
a^2 + b^2 = c^2
We know that the ladder is the hypotenuse because it is opposite the right angle.
a^2 + b^2 = 20^2
Substitute the length of the other side and solve.
a^2 + 17^2 = 20^2
a^2 + 289 = 400
a^2 = 111
The distance from the wall to the bottom of the ladder is the square root of 111 or approximately 10.5357 feet
5 0
3 years ago
(HELP FAST )What is the solution to this system of equations? *
Phantasy [73]

Answer:

(1,3) should be the answer due to the fact that both lines intersect at that point.

Step-by-step explanation:

8 0
2 years ago
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