The function f(x) = x² then the required function exists g(x) = -x²- 4.
<h3>What is a function?</h3>
The function exists described as y = f(x).
In mathematics, a function from a set X to a set Y allocates to each element of X exactly one element of Y. The set X exists named the domain of the function and the set Y exists named the codomain of the function. Functions stood originally for the idealization of how a variable quantity relies on another quantity.
For every x there exists a certain value of y.
From the graph g(x) exists reflection of f(x) at y = -4.
So g(x) = -f(x) - 4, the negative sign for reflection.
g(x) = -x² - 4
The required function exists g(x) = -x² - 4.
Therefore, the correct answer is option D. g(x) = -x² - 4.
To learn more about functions, refer to:
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The complete question is:
F(x) = x². What is g(x)?
A. g(x) = x² - 4
B. g(x) = x² + 4
C. g(x) = -4x²
D. g(x) = -x² - 4
Answer:
Simplified form of 3/4 - 1/6 v + 7/15 v - 1/2 is (1/4) - (-3/10 v)
Step-by-step explanation:
To simplify: 3/4 - 1/6 v + 7/15 v - 1/2
We can simplify this as:
3/4 - 1/2 - 1/6 v + 7/15 v
or (3/4 - 1/2) - (1/6 v - 7/15 v)
or (1/4) - (-3/10 v)
or (1/4) + (3/10 v) , This is the simplified answer.
So we got, 3/4 - 1/6 v + 7/15 v - 1/2 = (1/4) - (-3/10 v)
Answer:
55/4
Explanation:
Let's solve your equation step-by-step.
4
/5x−8=3
Step 1: Add 8 to both sides.
4
/5x−8+8=3+8
4
/5
x = 11
Step 2: Multiply both sides by 5/4.
(
5
/4
)*(
4
/5
x)=(
5
/4
)*(11)
x= 55/4
Answer:
x=
55
/4
Hope that helps :)
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Hello from MrBillDoesMath!
Answer:
For 0 <= x < =40 the function is that of the straight line 15x which has slope 15. Note that at x = 40 the value of the function is 15(4) =600
For x > 40 , the function is another straight line but with slope 20. This line is steeper than the 15x line but for x near, but slightly greater than 40, the value is close to 600 + 20 (40-40) or 600 + 20(40-40) = 600. This is the same value as the first line, 15x, at x = 40.
In summary, the graph of p(x), from 0 <= x <=40, is a line of slope 15 and for x>40 is a line of slope 20. p(x) has a removable discontinuity at x = 40 because p(x) approaches 600 as x approaches 40, regardless of the method of approach (i.e. whether x approaches 40 from values less than 40 or from values greater than 40)
Thank you,
MrB
