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MakcuM [25]
3 years ago
13

PLEASE HELP!!! Rita got up early this morning to hike into the mountains and watch the sunrise.

Mathematics
1 answer:
FromTheMoon [43]3 years ago
4 0

Answer:

B

Step-by-step explanation:

So, when she went downhill, she lost height (or subtracted height in this case)

But, when she climbed up 10 more meters, she gained 10 meters of height.

Therefore, is you use 47-36+10, you would get her height.

Hope this helps :)

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cricket20 [7]
You use pemdas and they both equal to 77. So yes they are equivalent.
8 0
3 years ago
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(3+3+8-9)+(66-6)6=<br><br><br> Please give correct answer if you a brainlest
yanalaym [24]

Answer:

365

Step-by-step explanation:

3+3=6+8=14-9=5+360=365                                                                                                                  

                              /\

                           66-6=60*6=360

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3 years ago
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What is the first step in solving, 3x - 12y=5 3y -x=9, using the elimination method
mote1985 [20]
3x-12y = 5
-x+3y = 9

First step is to make the coefficient of either x or y same.

3x-12y = 5
(-x+3y = 9)3

3x-12y = 5
-3x+9y = 27

-4y = 32
y = -8
3 0
4 years ago
Identify an equation in point-slope form for the line parallel to y = -
inessss [21]
It wouldn’t be any of those- because its in point-slope form ( y-y1=m(x-x1) ) the slope is -2/3, then the -5 (y) turns to +5 because there’s 2 negatives- since the x is positive it stays subtraction

The Correct equation would be y+5=-2/3(x-4)

Hope that helps :)
7 0
3 years ago
3 cards are drawn from a standard deck without replacement. What is the probability that at least one of the cards drawn is a re
Rudik [331]

Answer: \dfrac{15}{17}

Step-by-step explanation:

Total number of cards in a deck = 52

Number of red cards = 26

Number of cards not red =

Number of ways to draw not red cards = ^{26}C_3

Total ways to draw 3 cards = ^{52}C_3

The probability that none of three cards are red = \dfrac{^{26}C_3}{^{52}C_3}

=\dfrac{\dfrac{26!}{3!(26-3)!}}{\dfrac{52!}{3!(52-3)!}}  [∵ ^nC_r=\dfrac{n!}{r!(n-r)!}]

=\dfrac{\dfrac{26\times25\times24\times23!}{(23)!}}{\dfrac{52\times51\times50\times49!}{3!(49)!}}=\dfrac{2}{17}

Now , the probability that at least one of the cards drawn is a red card = 1- Probability that none cards are red

=1-\dfrac{2}{17}=\dfrac{17-2}{17}=\dfrac{15}{17}

Hence, the required probability = \dfrac{15}{17}

6 0
3 years ago
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