$\tan 3x=\frac{\sqrt{3} }{3} =\frac{1}{\sqrt{3} } =tan\frac{\pi }{6} =tan (n\pi +\frac{\pi }{6} )\\3x=n\pi +\frac{\pi }{6} =\frac{(6n+1)\pi }{6} \\x=\frac{(6n+1)\pi }{18} \\where~x~is~an~integer.$

Step-by-step explanation:

tan 3x=\frac{\sqrt{3} }{3} =\frac{1}{\sqrt{3} } =tan\frac{\pi }{6} =tan (n\pi +\frac{\pi }{6} )\\3x=n\pi +\frac{\pi }{6} =\frac{(6n+1)\pi }{6} \\x=\frac{(6n+1)\pi }{18} \\

where~x~is~an~integer.

6 0

2 years ago

Karina put a $300 pair of earrings on layaway by making a 10% down

abruzzese [7]

Answer:

8 weeks is the right APEX ANSWER

7 0

2 years ago

Milo is volunteering at a food pantry. In the first hour, he packs 3 boxes every

garri49 [273]

14 boxes per hour
60/5=12
12*3=36
60/6=10
10*5=50
50-36=14

5 0

2 years ago