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4 years ago

What is the y-intercept of the function f (x)=-2/9x + 1/3

Mathematics

1 answer:

Alina [70]4 years ago

5 0

Because this equation is in slope-intercept form, we can immediately tell the y-intercept is 1/3.

Slope intercept form:

y = mx + b

m = slope

b = y-intercept.

<h3>The y-intercept is 1/3.</h3>

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Please help me with this. Just have to write the equation. If you can solve, then you get brainliest guaranteed!

Temka [501]

x = player1

y = player 2

z = player 3

y = 2x or 1/2 y =x

y = z-10 or z = y+10

x+y+z=70

substitute x= 1/2 y and z = y+10 into the above equation

1/2y + y + y+10 = 70

2.5 y + 10 = 70

subtract 10 from each side

2.5 y = 60

divide by 2.5 on each side

y = 60/2.5

y =24

x = 1/2 y

x = 1/2 *24 = 12

z = y+10 = 24+10 = 34

The three players scored 12, 24, 34

4 0

3 years ago

Read 2 more answers

A conical vessels with base radius 5 cm and height 24cm is full of water this water is emptied into a cylindrical vessel of base

Aliun [14]

Answer:

$2\ cm$

Step-by-step explanation:

$We\ are\ given\ that,\\Radius\ of\ the\ conical\ vessel=5\ cm\\Height\ of\ the\ conical\ vessel=24\ cm\\Hence,\\As\ we\ know\ that,\\Volume\ of\ a\ cone=\frac{1}{3}\pi r^2h\\Hence,\\The\ volume\ of\ the\ conical\ vessel=\frac{1}{3}\pi (5)^224= \frac{1}{3}\pi 25*24=200\pi \\Hence,\\The\ volume\ of\ the\ conical\ vessel=The\ amount\ of\ water\ filled\ in\ it\\Hence,\\The\ amount\ of\ water\ filled\ in\ the\ conical\ vessel=200\pi\\Lets\ consider\ the\ cylindrical\ vessel:\\Volume\ of\ a\ cylinder=\pi r^2h$

$As\ we\ are\ not\ said\ that\ the\ cylindrical\ vessel\ was\ empty,\ let\ its\ initial\\ height\ be\ h_1\\Radius\ of\ the\ Cylindrical\ vessel=10\ cm\\Initial\ height\ of\ the\ cylindrical\ vessel=h_1\\Initial\ volume\ of\ the\ cylindrical\ vessel=\pi *10^2*h_1=100h_1\pi \\Initial\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi \\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=Final\ amount\ of\ water\\ in\ the\ cylindrical\ vessel +Amount\ of\ water\ in\ conical\ vessel$

$Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi +200\pi \\Now,\\Let\ the\ final\ height\ be\ h_2\\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=\pi *10^2*h_2=100h_2\pi \\Hence,\\100h_2\pi =100h_1\pi +200\pi \\Hence,\\100h_2=100h_1+200\\100h_2-100h_1=200\\100(h_2-h_1)=200\\h_2-h_1=2\\Hence,\\As\ the\ rise\ in\ level\ is\ the\ difference\ between\ the\ initial\ and\ final\\ heights:\\The\ rise\ in\ level\ of\ water=2\ cm$

8 0

3 years ago

What error did zacharias make?

qwelly [4]

The equation 0 = -2x2 5x - 3 was the quadratic formula that Zacharias used. However, he started substituting as:
Quadratic formula as x = ; substitution as x

The errors he made: he mistakenly used the negative (-) and postive (+)
* -5 should have been 5
* 52 should have been -52
* both the numerator and the denominator should have been -2 instead of 2

7 0

3 years ago

Read 2 more answers

38+39+40+41+...+130+131

aliya0001 [1]

Answer:

419

Step-by-step explanation:

the answer is 419 because 38+39=77+40=117+41=158+130=288+131=419

hope my math is correct =)

6 0

3 years ago

What is the surface area of a right rectangular prism with the length of 10 inches width of 8 inches and a height of 1.5 inchess

Contact [7]

Answer: Option 3

Step-by-step explanation: Option (3) is correct.The surface area of a rectangular prism of given dimension is 170 square inches.Step-by-step explanation:Given : a rectangular prism whose base is 5 inches by 6 inches and whose height is 5 inches.We have to find the surface area of a rectangular prism of given dimension.Since a rectangular prism whose base is 5 inches by 6 inchesThat is length (l)= 5 inches Width (w) = 6 inches and height (h) = 5 inches.Also . Substitute, we have,simplify , we have,surface area of a rectangular prism = 170 inches²Thus, the surface area of a rectangular prism of given dimension is 170 square inches

8 0

3 years ago