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3 years ago

10

What value of x is in the solution set of 3(x-4) > 5x + 2?

1 answer:

Natasha_Volkova [10]3 years ago

8 0

Answer:

x < -7

Step-by-step explanation:

Eliminate parentheses:

3x -12 > 5x +2

-14 > 2x . . . . . . . . . add -2-3x

-7 > x . . . . . . . . . . . divide by 2

Any value of x less than -7 is in the solution set.

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$y < \dfrac{2}{3}x\\\\y=\dfrac{2}{3}x\\\\for\ x=0\to y=\dfrac{2}{3}(0)=0\to(0,\ 0)\\\\for\ x=3\to y=\dfrac{2}{3}(3)=2\to(3,\ 2)\\\\y\geq-x+2\\\\y=-x+2\\\\for\ x=0\to y=-0+2=2\to(0,\ 2)\\\\for\ x=2\to y=-2+2=0\to(2,\ 0)$

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the dotted line. shadow under the line

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