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galben [10]
3 years ago
13

Now, use the substitution or elimination method to find the point of

Mathematics
1 answer:
Leni [432]3 years ago
7 0
Pls where is the question actually??
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Tracy is finding the equation of a median-median line. She found that the equation of the line through the first and third summa
rodikova [14]
<span>1) Find the equation of the line that passes through (x1, y1) and (x3, y3).
We have it: </span>y = 0.4x + 38<span>2) Find the equation of the line parallel to the previous line that passes through (x2, y2). 
</span><span>That is: y = 0.4x + 59
</span><span>3) Find the weighted average of the
y-intercepts.  b=(b1+b2+b1)/3 = (38+59+38)/3
                      b= 45
The median-median line is the line parallel to the previous two lines with the weighted y-intercept.Hence, Y = 0.4 x + 45 is the answer</span>
7 0
3 years ago
Part A: The club has learned from experience over the years that when they do not charge an admission fee, attendance is 800 peo
sesenic [268]

Answer:

750

Step-by-step explanation:

800 - 8p = 750

5 0
3 years ago
0 A public beach in Arkansas charges non- residents $12 per day for a fishing license and $3.50 per day for live bait. Arkansas
vfiekz [6]
Non Residents:
f(x)= money in $ paid.
x=number of days.

f(x)=x(12+3.5)=15.5 x

f(x)=15.5x

Arkansas residents
f(x)=money in $ paid.
x=number of days.

f(X)=x+174

Now, we equate functions:

15.5x=x+174    (this is the equation)
15.5x-x=174
14.5x=174
x=174 / 14.5=12

Answer: the number of days is 12 days. The ecuation has one solution, because when I has solved it, I have had one solution.
6 0
3 years ago
Which relation is a function?
Oksanka [162]
It’s B because the domain(x) doesn’t repeat like the other options.
5 0
3 years ago
This shape is made using three semicircles The smaller semicircle have diameters of 10cm Calculate the shaded area Take 3.142 an
AleksandrR [38]

Answer:

The shaded area is 314.2 cm²

Step-by-step explanation:

Here we note that the shape consists of two small circles and one larger circle

The diameter of the larger semicircle is subtended by the two smaller semicircles, the small semicircle closer to the left of the internal circumference of the larger semicircle is shaded one while the one on the right is without color,

Therefore,

Diameter of larger semicircle = 2 × 10 = 20 cm

Based on the diagram, the shaded area is observed to be;

Shaded area = Area of semicircle formed by larger diameter or 20 cm + Area area formed by the small semicircle close to the right of the internal circumference of the larger semicircle - Area area formed by the other smaller semicircle

Since the diameter and therefore the areas of the two small semicircles are equal, we have;

Shaded area = Area formed by the complete larger semicircle = Area of semicircle formed by larger diameter or 20 cm

∴ Shaded area = π·D²/4 = π×20²/4 = 100×3.142 cm² = 314.2 cm².

6 0
3 years ago
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