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galben [10]
3 years ago
13

Now, use the substitution or elimination method to find the point of

Mathematics
1 answer:
Leni [432]3 years ago
7 0
Pls where is the question actually??
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One section in the auditorium has 59 rows
diamong [38]
2,242
Because if there are 59 rows of seats in that section and 38 seats in each row you would do 59x38
8 0
3 years ago
What is the solution to the system -2x + y = 6 and y= 2x - 3?
Irina18 [472]
<span>
replace y= 2x - 3 into </span>-2x + y = 6 

-2x + 2x - 3  = 6 
<span>
- 3 = 6 .....no solutions....


</span>
8 0
3 years ago
Find a power series representation for the function. (Give your power series representation centered at x=0 .) f(x)=15+x
Anna71 [15]

Answer:

f(x) = \sum\limits^{\infty}_{n=0} \frac{-(1)^n\cdot x^n}{5^{n+1}}

Step-by-step explanation:

Given

f(x) = \frac{1}{5 + x}

Required

The power series centered at x = 0

We have:

f(x) = \frac{1}{5 + x}

Factor out 5 from the denominator

f(x) = \frac{1}{5(1 + \frac{x}{5})}

Rewrite as:

f(x) = \frac{\frac{1}{5}}{(1 + \frac{x}{5})}

Further, rewrite as:

f(x) = \frac{1}{5}(1 + \frac{x}{5})^{-1}

Expand the bracket

f(x) = \frac{1}{5}(1 - \frac{x}{5} + (\frac{x}{5})^2 - (\frac{x}{5})^3+..........)

Evaluate all exponents

f(x) = \frac{1}{5}(1 - \frac{x}{5} + \frac{x^2}{25} - \frac{x^3}{125}+......)

Open brackets

f(x) = \frac{1}{5} - \frac{x}{5^2} + \frac{x^2}{5^3} - \frac{x^3}{5^4}+......

Notice the pattern as:

f(x) = \frac{1}{5} - \frac{x}{5^2} + \frac{x^2}{5^3} - \frac{x^3}{5^4}+......\± \frac{x^n}{5^{n+1}}

So, the power series is:

f(x) = \sum\limits^{\infty}_{n=0} \frac{-(1)^n\cdot x^n}{5^{n+1}}

4 0
3 years ago
A furnace delivers 8.0 × 104 btu per hour. how many kilocalories per hour is this?
vazorg [7]
For this case the first thing you should know is the following unit conversion.
 1 BTU = 0.25 Kilocalories
 We then have the following numerical value:
 8.0 * 10 ^ 4 \frac{BTU}{h}
 Applying the conversion of units we have:
 8.0 * 10 ^ 4 \frac{BTU}{h} * 0.25 \frac{Kcal}{BTU}
 Canceling units we have:
 20000 \frac{Kcal}{h}
 Answer:
 
This is 20000 kilocalories per hour
 
20000 \frac{Kcal}{h}
6 0
3 years ago
Please please please help with this
andrew11 [14]
✔️0 < x < 1
X -3 < x < -2
✔️-1 < x < 0
X 2 < x < 3

Here's how you do it: you go to the graph, and go to the area where the function connects with 0, and follow it to the path where it connects with 1. Is that specific line decreasing or increasing? Nevermind what happens to it after/before those specific numbers, you're focusing on whether the function is increasing or decreasing from 0 to 1. The same apply to the other 3.
8 0
3 years ago
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