Answer:
1. ASA
2. AAS
3. AAS
4. SSS
5. SSS
6. not sure which triangles are number 6
7. SAS
A trapezoid<span> is a quadrilateral with one pair of parallel sides, and the </span>formula for<span> the area of a </span>trapezoid<span> is 1/2 times (base 1 + base 2) times height</span>
The function is k(x) = 512 · x .
Try 'A': k(2/3) = (512) · (2/3) = 341.33... not 64
Try 'B': k(4/9) = (512) · (4/9) = 257.55... not 16
Try 'C': k(1/3) = (512) · (1/3) = 170.66... not 8
Try 'D': k(2/9) = (512) (2/9) = 113.77... not 8 .
So far, it looks like NONE of the choices is correct.
But wait ! There's more !
What if the actual function is k(x) = 512ˣ
that is, 512 raised to the 'x' power ?
That would be a horse of a different cruller.
Let's try THAT out.
First, here are two facts that we'll need:
==> 512 ^ 1/3 = 8
and
==> 512 ^ 1/9 = 2 .
OK. NOW ...
Try 'A': k(2/3) = (512) ^ 2/3 = 8^2 = 64 yes !
Try 'B': k(4/9) = (512) ^ 4/9 = 2^4 = 16 yes !
Try 'C': k(1/3) = (512) ^ 1/3 = 8 yes !
Try 'D': k(2/9) = (512) ^ 2/9 = 2^2 = 4 not 8 .
So here's what we have learned:
-- The function in the question is actually k(x) = 512 ^ x
-- Choice-D is the incorrect one.
This is a Logic Problem. So we need to use operators to solve this problem. There are several operators in logic. Operators can be <em>monadic or dyadic</em>. A <em>monadic operator</em> operates on a single simple statement. Other operators will all be <em>dyadic operators </em>because they operate on two simple statements.
So we have the following simple statements:
p: the book is interesting
q: the book has pictures
Thus, let's solve each notation.
First. p ∧ q
<u>Conjunction operator.</u> <span>The conjunction operator creates a compound statement such that in order for the whole statement to be true, <em>each simple statement must be true. </em>
</span><u>Symbol:</u> & (also ∧)
<u>Parts of conjunction:</u> <span>Two simple statements joined by the conjunction symbol.
</span>
<u>Answer:</u>
<span>p ∧ q: The book is interesting and the book has pictures.
</span>Second. p ↔ q
<u>Bi-conditional operator:</u> The bi-conditional operator creates a compound statement such that in order for the whole statement to be true <em>each simple statement has to have the same truth value.</em>
<u>Symbol:</u> ↔
<u>Parts of bi-conditional:</u> Two simple statements joined by the bi-conditional symbol.
<u>Answer:</u>
p ↔ q: The book is interesting if and only if the book has pictures.
Third. p ∨ q
<u>Disjunction operator:</u> The disjunction operator creates a compound statement that is <em>true if either simple statement is true but false if both simple statements are false.</em>
<u>Symbol:</u> ∨
<u>Parts of disjunction: </u>Two simple statements joined by the disjunction symbol
<u>Answer:</u>
p ∨ q: The book is interesting or the book has pictures.
Fourth. p → q
<u>Conditional operator:</u> T<span>he conditional operator creates a compound statement that sets up a condition for something to be true. <em>If the condition is met, the statement is true.</em>
</span>
<u>Symbol:</u> →
<u>Parts of conditional:</u> <span>Two simple statements joined by the conditional symbol. The first simple statement in a conditional is called the </span><em>antecedent</em><span> and the second simple statement is called the </span><em>consequent</em><span>.</span>
<u>Answer:</u>
p → q: If the book is interesting then the book has pictures.
Answer:
1
Step-by-step explanation: