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bonufazy [111]
3 years ago
11

If the mass is 10 the volume is

Mathematics
1 answer:
AysviL [449]3 years ago
4 0
If he mass is 10 then the volume is 100
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253,248,243, find the 49th term.
denpristay [2]

Answer:

13

Step-by-step explanation:

the difference is -5

  • nth=a+(n-1)d
  • a=253,n=49,d=5
  • 253+(49-1)×-5
  • 253+48×-5
  • 253+(-240)
  • 253-240=13

the 49th term is 13

8 0
2 years ago
Please solve for X and show step by step equation
larisa [96]

Answer:

6

Step-by-step explanation:

Firstly, this is the pythagoreans theorem a^2+b^2=c^2

Now that we know that, we will solve for x.

(x+2)^2+x^2=100 ( The 100 is just 10 squared )

Finally, you solve for x and get 6.

3 0
2 years ago
Read 2 more answers
22. Mona is in her garden jumping on stones (as shown below).
iris [78.8K]

\large\green{\sf\boxed{Given:-}}

<u>Mona starts from 68th stone</u>

<u>She jumps</u><u> </u><u>23</u><u> </u><u>stones</u><u> </u><u>ahead</u><u> </u>

<u>Then</u><u> </u><u>she</u><u> </u><u>jumps</u><u> </u><u>28</u><u> </u><u>stones</u><u> </u><u>back</u>

\large\red{\sf\boxed{To \:find:-}}

<em>Her final position=?</em>

\large{|\underline{\mathtt{\red{S}\blue{o}\orange{l}\pink{u}\blue{t}\purple{i}\green{o}\red{n}\blue{:}\orange{-}}}}

  • Add 23 in 68 [Given]

\begin{gathered}\\ \sf\longmapsto 68+23=91\end{gathered}

  • Subtract 28 from 91

\begin{gathered}\\ \sf\longmapsto 91-28=Her\:final\:position\end{gathered}

\begin{gathered}\\ \sf\longmapsto =63\end{gathered}

  • To find how much stones she is ahead or back we will Subtract 63 from 68 which was her initial position.

\begin{gathered}\\ \sf\longmapsto 68-63=5\end{gathered}

So, Mona will be <em><u>5</u></em><em><u> </u></em><em><u>stones</u></em><em><u> </u></em><em><u>behind</u></em><em><u> </u></em><em><u>from</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>starting</u></em><em><u> </u></em><em><u>stone</u></em><em><u>.</u></em>

☯️Hence, Option C is correct

7 0
2 years ago
This is integrated math2, i’m so lost idk what this is
igor_vitrenko [27]

Answer:

A. SAS

Step-by-step explanation:

In\:\triangle ABM \:\&\:\triangle CBM\\\overline{AB} \cong \overline{CB}.... (given) \\\angle ABM \cong \angle CBM....(given) \\\overline{BM} \cong \overline{BM}.... (common) \\\therefore \triangle ABM \:\cong\:\triangle CBM..... (SAS\: Postulate)

7 0
3 years ago
The school store has 750 packs of crayons.each pack has 12 markers in it.how many markers are there in all
kirza4 [7]
There are 9,000 markers in total

750 x 12 = 9,000
3 0
3 years ago
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