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bonufazy [111]
3 years ago
11

If the mass is 10 the volume is

Mathematics
1 answer:
AysviL [449]3 years ago
4 0
If he mass is 10 then the volume is 100
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Which of the following rational functions is graphed below?
nata0808 [166]

Answer:

B

Step-by-step explanation:

The function's zeroes results in vertical asymptotes. As one is at x = 1 and the other at x = -2, the zeroes must be (x-1) and (x+2), which only B contains in the numerator.

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3 years ago
Solve 4x-5/5=3<br> thankyou
atroni [7]

Answer:

x = 1

Step-by-step explanation:

4x - 5/5 = 3

4x - 1 = 3

add 1 to each side of the equation:

4x = 4

divide both sides by 4:

x = 1

3 0
3 years ago
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Name the set or sets of numbers to which the square root of 28 belongs to.
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SOLUTION: name the set or sets of numbers on a numbers to which each real number bleongs question 1) negative square root of 64 question 2) 8/3 question 3) square root 28 questio. , so it is a Real Number, Rational Number, and Integer. is a fraction, so it is a Real Number and a Rational Number.

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3 years ago
What are the right answers and how do you find it?
IceJOKER [234]
This is the correct answers

8 0
4 years ago
Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:
Goshia [24]

Answer:

case 1 = 2592

case 2 =  729

case 1 + case 2 =  2916

(this is not a direct adition, because case 1 and case 2 have some shared elements)

Step-by-step explanation:

Case 1)

6 digits numbers that can be divided by 25.

For the first four positions, we can use any of the 6 given numbers.

For the last two positions, we have that the only numbers that can be divided by 25 are numbers that end in 25, 50, 75 or 100.

The only two that we can create with the numbers given are 25 and 75.

So for the fifth position we have 2 options, 2 or 7,

and for the last position we have only one option, 5.

Then the total number of combinations is:

C = 6*6*6*6*2*1 = 2592

case 2)

The even numbers are 2,4 and 6

the odd numbers are 3, 5 and 7.

For the even positions we can only use odd numbers, we have 3 even positions and 3 odd numbers, so the combinations are:

3*3*3

For the odd positions we can only use even numbers, we have 3 even numbers, so the number of combinations is:

3*3*3

we can put those two togheter and get that the total number of combinations is:

C = 3*3*3*3*3*3 = 3^6 = 729

If we want to calculate the combinations togheter, we need to discard the cases where we use 2 in the fourth position and 5 in the sixt position (because those numbers are already counted in case 1) so we have 2 numbers for the fifth position and 2 numbers for the sixt position

Then the number of combinations is

C = 3*3*3*3*2*2 = 324

Case 1 + case 2 = 324 + 2592 = 2916

4 0
3 years ago
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