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harkovskaia [24]
3 years ago
13

Lines AC and BD intersect at E. A figure. What is the measure of angle BEC?

Mathematics
1 answer:
stepladder [879]3 years ago
6 0

Answer:

Angle BEC = 108°

Step-by-step explanation:

Vertical angles formed when two straight lines intersect are always congruent to each other. That is, the vertical opposite angles formed are of the same measure.

Angle AED = 108°

Angle AED and angle BEC are vertical opposite angles form by intersecting lines, therefore, angle AED = angle BEC.

Angle BEC = 108°

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Can someone please help me with this? I don’t understand what is given.
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\bf BC=2BA\\ BE = 2BD \end{cases} \cfrac{BC}{BE}=\cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~BA}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~BD}\implies \cfrac{BC}{BE}=\cfrac{BA}{BD}\impliedby \begin{array}{llll} \textit{equal ratio of sides}\\ \textit{similar triangles} \end{array}

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maxonik [38]

Answer:

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Step-by-step explanation:

<em>We </em><em>can </em><em>solve </em><em>this </em><em>by </em><em>eliminating</em><em> </em><em>given </em><em>detail </em><em>of </em><em>A.</em>

AC=13 , AB=10

<u>To </u><u>find </u><u>BC,</u><u> </u><u>We </u><u>minus </u><u>A</u><u>C</u><u> </u><u>With </u><u>AB</u>

BC= AC-AB

<u>BC=3</u>

3 Is the final answer

I hope this helps, dont hesitate to ask for any question.

Mark me as brainliest is appreciated.Tq!!

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