I think these are the sums of perfect cubes.
A = (2x²)³ + (3)³
B = (x³)³ + (1)³
D = (x²)³ + (x)³
E = (3x³)³ + (x^4)³
Answer:
T is at (13,-6)
Step-by-step explanation:
x-coordinate of T: from -9 to 2, there's 11 units, so you add 11 to 2 to find the x-coordinate of T, which is 13.
y-coordinate of T: from 4 to -1 there's -5 units, so you subtract 5 from -1 to find the y-coordinate of T, which is -6.
7(x-2) +3x=46
7x-14+3x=46
10x-14=46
10x=60
X=6
Answer:
The resulting three-dimensional object will be a cone
Step-by-step explanation:
Plot the figure to better understand the problem'
we have
a triangular cross-section with coordinates at (1, 1), (1, 4), and (3, 1)
The draw in the attached figure
we know that
When rotating a a right triangle about a leg, the three dimensional figure formed is a cone
The radius of the cone will be equal to the base of right triangle and the height of the cone will be equal to the height of the triangle
so
The radius of the cone will be equal to 2 units and the height of the cone will be 3 units
see the attached figure to better understand the problem
Answer:
C
Steps
The A equation is impossible (even if it looks like solvable with quadratic formula)
Have a good day