Question

11/ 42 Marks

Answer 1

Answer:

(a)x=128 degrees

(b)$\angle APD\neq 116^\circ$

Step-by-step explanation:

$\angle ABD+\angle CBD =180^\circ (Linear Postulate)\\\angle ABD+116^\circ =180^\circ\\\angle ABD=180^\circ-116^\circ\\\angle ABD=64^\circ$

(a) Now:

$\angle AOD=2 \times \angle ABD (Angle at the centre is twice the angle at the circumference)\\x=2 \times 64^\circ\\x=128^\circ$

(b)

$\angle APD=2 \times \angle ABD (Inscribed Angle Theorem)\\\angle APD=2 \times 64^\circ\\ \angle APD=128^\circ$

$\angle APD\neq 116^\circ$