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Orlov [11]
3 years ago
10

Please help me answer this question only number 1

Mathematics
1 answer:
slavikrds [6]3 years ago
6 0

Answer:

Sorry can't see really can you tell me what it says i can try and figure it out for you then

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Alex_Xolod [135]

Answer:

where is question ???

Step-by-step explanation:

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Lonny is serving soup for charity. Each bowl holds 2.15 cups of soup. How many bowls will Lonny use if he serves a total of 94.6
azamat

Answer: 44 bowls

Step-by-step explanation:

94.6 divided by 2.15 = 44 bowls of soup

***If you found my answer helpful, please give me the brainliest. :) ***

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Please help me out with this worksheet
Sindrei [870]
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3 0
3 years ago
There were 6 purple socks and 4 oraange socks without looking and then another without looking (or replacing the first). What is
shusha [124]

Answer:

The probability that he picked 2 purpled socks is <u>0.33</u>.

Step-by-step explanation:

Given:

Number of purple socks, n(P) = 6

Number of orange socks, n(O) = 4

Two socks are picked without replacement.

Now, total number of socks, n(T)=N(P)+n(O)=6+4=10

Probability of picking the first cap as purple cap is given as:

P(P1)=\frac{n(P)}{n(T)}\\\\P(P1)=\frac{6}{10}=\frac{3}{5}

Since there is no replacement, the number of socks decreases by 1. Also, if the first sock picked is purple, then number of purple socks is also decreased by 1.

Therefore, probability of picking the second cap as purple cap is given as:

P(P2)=\frac{n(P)-1}{n(T)-1}\\\\P(P2)=\frac{5}{9}

Now, probability that both the picked caps are purple is given by their probability product. This gives,

P(P1\ and\ P2)=P(P1)\times P(P2)\\\\P(P1\ and\ P2)=\frac{3}{5}\times\frac{5}{9}\\\\P(P1\ and\ P2)=\frac{3}{9}=\frac{1}{3}=0.33

Therefore, the probability that he picked 2 purpled socks is 0.33

4 0
3 years ago
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