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3 years ago

What’s the answer to this algebra question

Mathematics

1 answer:

natka813 [3]3 years ago

4 0

Answer:

x=9, x=7

Aka x= 9,7

Step-by-step explanation:

Oh goodie, factoring.

I used to be very good at this. My memory is a LITTLE rusty but let's see if we can bust out some penzoil and fix my aching joints (yes I just stole the quote from that terrible show, sue me), shall we?

1. x^2 - 11x + 68 = 5x +5

2. Chuck all the x variables to the left: x^2 - 16x + 68 = 5

3. Get rid of that pesky loser, 5, by subtracting from both sides of the equation (Note that it's important to remember LIKE TERMS, don't try subtracting 5 from 16x, you'll hurt yourself): x^2 - 16x + 68 - 5 = 5 - 5

New equation: x^2 - 16x + 63 = zilch (0)

4. Use AC method to factor: x2+bx+c. AC method definition: a pair of numbers whose product is c and whose sum is b: (x-9)(x-7)=0

5. Solve for x.

Booyah.

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Use the quadratic model d= -3p^2+168p-315 to predict d if p equals 15.

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3 years ago

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Andy is hanging wallpaper in his kitchen. He is able to cover of the walls in the room using 6 rolls of wallpaper. What is the n

Alchen [17]

Answer: Andy covers all the walls of his kitchen using 6 rolls of a wallpaper.

To Find:

Number of rolls used per wall.

Solution:

Since, we know that the shape of a kitchen is a cuboid.

And a cuboid has total 6 faces, with 4 walls, one roof and one floor.

So, total number of walls in Andy's kitchen = 4

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Step-by-step explanation:

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2 years ago

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tensa zangetsu [6.8K]

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3 years ago

Calculus 2

FinnZ [79.3K]

Answer:

See Below.

Step-by-step explanation:

We want to estimate the definite integral:

$\displaystyle \int_1^47\sqrt{\ln(x)}\, dx$

Using the Trapezoidal Rule, Midpoint Rule, and Simpson's Rule with six equal subdivisions.

The trapezoidal rule is given by:

$\displaystyle \int_{a}^bf(x)\, dx\approx\frac{\Delta x}{2}\Big(f(x_0)+2f(x_1)+...+2f(x_{n-1})+f(x_n)\Big)$

Our limits of integration are from x = 1 to x = 4. With six equal subdivisions, each subdivision will measure:

$\displaystyle \Delta x=\frac{4-1}{6}=\frac{1}{2}$

Therefore, the trapezoidal approximation is:

$\displaystyle =\frac{1/2}{2}\Big(f(1)+2f(1.5)+2f(2)+2f(2.5)+2f(3)+2f(3.5)+2f(4)\Big)$

Evaluate:

$\displaystyle =\frac{1}{4}(7)(\sqrt{\ln(1)}+2\sqrt{\ln(1.5)}+...+2\sqrt{\ln(3.5)}+\sqrt{\ln(4)})\\\\\approx18.139337$

The midpoint rule is given by:

$\displaystyle \int_a^bf(x)\, dx\approx\sum_{i=1}^nf\Big(\frac{x_{i-1}+x_i}{2}\Big)\Delta x$

Thus:

$\displaystyle =\frac{1}{2}\Big(f\Big(\frac{1+1.5}{2}\Big)+f\Big(\frac{1.5+2}{2}\Big)+...+f\Big(\frac{3+3.5}{2}\Big)+f\Big(\frac{3.5+4}{2}\Big)\Big)$

Simplify:

$\displaystyle =\frac{1}{2}(7)\Big(f(1.25)+f(1.75)+...+f(3.25)+f(3.75)\Big)\\\\ =\frac{1}{2}(7) (\sqrt{\ln(1.25)}+\sqrt{\ln(1.75)}+...+\sqrt{\ln(3.25)}+\sqrt{\ln(3.75)})\\\\\approx 18.767319$

Simpson's Rule is given by:

$\displaystyle \int_a^b f(x)\, dx\approx\frac{\Delta x}{3}\Big(f(x_0)+4f(x_1)+2f(x_2)+4f(x_3)+...+4f(x_{n-1})+f(x_n)\Big)$

So:

$\displaystyle =\frac{1/2}{3}\Big((f(1)+4f(1.5)+2f(2)+4f(2.5)+...+4f(3.5)+f(4)\Big)$

Simplify:

$\displaystyle =\frac{1}{6}(7)(\sqrt{\ln(1)}+4\sqrt{\ln(1.5)}+2\sqrt{\ln(2)}+4\sqrt{\ln(2.5)}+...+4\sqrt{\ln(3.5)}+\sqrt{\ln(4)})\\\\\approx 18.423834$

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3 years ago

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TEA [102]

Answer:

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sugar: 2 tbsps*5=10 tablespoons

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oil: 2 tbsps*5=10 tablespoons

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2 years ago