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Vanyuwa [196]
3 years ago
12

At 7:00 am, the temperature was -4℉. At 9:00 am, it was 8° warmer. What was the temperature at 9:00 am? *

Mathematics
1 answer:
Nana76 [90]3 years ago
8 0

<em>4℉.</em>

What we know about Degrees is that there is a<em> </em><u><em>Positive</em></u> type and a <u><em>negative</em></u> type.

(i.e: 30℉ is <u><em>positive</em></u> and -30℉ is <u><em>negative</em></u>.)

If the temperature was -4℉ at 7AM, then it is negative. If it goes up by an amount that is more than 4 then that negative will go up to a positive temperature. In this case: At 9AM it was 8° <u><em>warmer</em></u>.

<u><em>Warmer</em></u><em> is a </em><u><em>keyword</em></u><u>.</u> If it is warmer by an amount, Negative temperatures <u><em>will go up to a positive</em></u> and positive temperature <u><em>will just go up</em></u>. If it gets cooler, negative temperatures <u><em>will go down further</em></u> and positive temperatures <u><em>will go down to a negative</em></u>.

So lets work out this problem with our newfound knowledge.

-4° F at 7AM

8°  warmer at 9AM

-4 + 8 = 4.

<em>The temperature was 4°  at 9AM.</em>

-Snooky

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7 0
3 years ago
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yarga [219]

Answer:

x=-6 is an extraneous solution

Step-by-step explanation:

we have

\sqrt{-3x-2} =x+2

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solve the quadratic equation by graphing

The solution is x=-6 and x=-1

see the attached figure

<u><em>Verify each solution</em></u>

substitute the value of x in the original expression

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so

Is an extraneous solution

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4 0
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Step-by-step explanation:

\dfrac{100}{3 \times 5}

6 0
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