Solve for q 2/3=-1/3q

1 answer:

6 0

Q in (-oo:+oo)

2/3 = (1/3)*q // - (1/3)*q

2/3-((1/3)*q) = 0
   ddddddddd
   d    d
   d    d
(-1/3)*q+2/3 = 0    d    d
   d    d
2/3-1/3*q = 0 // - 2/3 d    d
   d    d
-1/3*q = -2/3 // : -1/3 d    d
   d    d
q = -2/3/(-1/3)    ddddddd dddddddd
   dd dd
q = 2    dd dd
dd dddd    dd
q = 2    dddddddddd    dddddddddddd

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OPTION A

OPTION B

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Step-by-step explanation:

Irrational numbers are the subset of real numbers. Their decimal representation neither form a pattern nor terminate.

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This is equal to $\frac{1}{\sqrt{2}}$ .

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OPTION B: $\sqrt{\frac{1}{8}}$

This is equal to $\frac{1}{2\sqrt{2}}$ . Using the same logic as Option A, we regard OPTION B to be irrational as well.

OPTION C: $\sqrt{\frac{1}{10}}$

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Both $\sqrt{5}$ and $\sqrt{2}$ are irrational. So, the product and the reciprocal of the product is irrational as well. So, OPTION C is an irrational number.

OPTION D: $\sqrt{\frac{1}{16}}$

16 is a perfect square and is a rational number. $\frac{1}{\sqrt{16}}$ = $\frac{1}{4}$ . This is equal to 0.25, a terminating decimal. So, OPTION D is a rational number.