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4 years ago

Place value 100unite and ones only

1 answer:

maks197457 [2]4 years ago

5 0

10 units is 100 because 1 unit equals 10 ones. 100 ones is 100 because one one is one. I don't know if this answers your question I didn't really get what you were asking.

You might be interested in

The difference of the squares of two positive consecutive even integers is 4444. find the integers. use the fact that, if x rep

Sergio [31]

Remember that the formula for the difference of squares is $a^2 - b^2$ , where $a$ and $b$ are expressions or values.

In this case, we have two expressions, $x$ and $(x + 2)$ . We are also given that their difference of squares is 4444. Using the formula, we can say:

$(x + 2)^2 - x^2 = 4444$

Now, we can solve for $x$ :

$(x + 2)^2 - x^2 = 4444$

$(x^2 + 4x + 4) - x^2 = 4444$

$4x + 4 = 4444$

$4x = 4440$

$x = 1110$

We now know that the first number is 1110. To find the second number, we must add 2 to the first number, which means that the second number, represented by $(x + 2)$ , is equal to 1112.

Our two numbers are 1110 and 1112.

7 0

3 years ago

Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra

katen-ka-za [31]

You made a mistake with the probability $p_{j}$ , which should be $p_{i}$ in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer $j$ , is given by:

(1) $\frac{p_{j} }{1-d_{i}p_{i} } , if j \neq i,$ and

(2) $\frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} } , if j = i.$

so we can say:

$A$ is the event that you search drawer $i$ and find nothing,

$B$ is the event that you search drawer $i$ and find the paper,

$C_{k}$ is the event that the paper is in drawer $k, k = 1, ..., n.$

this gives us:

$P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}$

$P(A) = 1 - P(B) = 1 - d_{i} p_{i}$

Solution to Part (1):

if $j \neq i$ , then $P(A \cap C_{j} ) = P(C_{j} )$ ,

this means that

$P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)} = \frac{P(C_{j} )}{P(A)} = \frac{p_{j} }{1-d_{i}p_{i} }$

as needed so part one is solved.

Solution to Part(2):

so we have now that if $j$ = $i$ , we get that:

$P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}$

remember that:

$P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}$

this implies that:

$P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )$

so we just need to combine the above relations to get:

$P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} }$

as needed so part two is solved.

8 0

4 years ago

Determine the intercepts of the line.<br> y = -2x-21<br> X-intercept:<br> y-intercept:

vfiekz [6]

Ummm eeee i dont knowwwe

4 0

3 years ago

Of the pets in the pet show, 10/12 are cats. 6/10 of the cats are calico cats. What fraction of the cats are calico cats?

Lera25 [3.4K]

Answer:

6/10, simplified 3/5

Step-by-step explanation:

kinda tricky, but the fraction is stated right out.

8 0

3 years ago

Read 2 more answers

Find the distance between the points<br><br> (1,8) and (-3,8)

Vilka [71]

Answer:

<h2>4 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

From the question we have

$d = \sqrt{ {(1 - - 3)}^{2} + ({8 - 8})^{2} } \\ = \sqrt{ ({1 + 3})^{2} } \\ = \sqrt{ {4}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \\ = \sqrt{16} \: \: \: \: \: \: \: \: \: \: \:$

We have the final answer as

<h3>4 units</h3>

Hope this helps you

6 0

3 years ago

Read 2 more answers