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2 years ago

Need help with a math question

Mathematics

1 answer:

Lilit [14]2 years ago

6 0

Answer:

$d =\sqrt{(b-0)^2 +(c-a)^2}$

Step-by-step explanation:

We know that the distance between two points is calculated using the following formula

$d =\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

In this case we look for the RS distance

Then

The starting point is: (0, a)

The final point is (b, c)

$x_2 = b\\x_1 = 0\\y_2 = c\\y_1=a$

The distance is:

$d =\sqrt{(b-0)^2 +(c-a)^2}$

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F(x)=4^x and g(x)=4^x+2

dsp73

Given:

The two functions are:

$f(x)=4^x$

$g(x)=4^x+2$

To find:

The type of transformation from f(x) to g(x) in the problem above and including its distance moved.

Solution:

The transformation is defined as

$g(x)=f(x+a)+b$ .... (i)

Where, a is horizontal shift and b is vertical shift.

If a>0, then the graph shifts a units left.
If a<0, then the graph shifts a units right.
If b>0, then the graph shifts b units up.
If b<0, then the graph shifts b units down.

We have,

$f(x)=4^x$

$g(x)=4^x+2$

The function g(x) can be written as

$g(x)=f(x)+2$ ...(ii)

On comparing (i) and (ii), we get

$a=0,b=2$

Therefore, the type of transformation is translation and the graph of f(x) shifts 2 units up to get the graph of g(x).

3 0

2 years ago

Needdd hellpppppssssssss

Ratling [72]

Answer:

Choice number one:

$\displaystyle \frac{5}{10}\cdot \frac{4}{9}$ .

Step-by-step explanation:

Let $A$ be the event that the number on the first card is even.
Let $B$ be the event that the number on the second card is even.

The question is asking for the possibility that event $A$ and $B$ happen at the same time. However, whether $A$ occurs or not will influence the probability of $B$ . In other words, $A$ and $B$ are not independent. The probability that both $A$ and $B$ occur needs to be found as the product of

the probability that event $A$ occurs, and
the probability that event $B$ occurs given that event $A$ occurs.

5 out of the ten numbers are even. The probability that event $A$ occurs is:

$\displaystyle P(A) = \frac{5}{10}$ .

In case A occurs, there will only be four cards with even numbers out of the nine cards that are still in the bag. The conditional probability of getting a second card with an even number on it, given that the first card is even, will be:

$\displaystyle P(B|A) = \frac{4}{9}$ .

The probability that both $A$ and $B$ occurs will be:

$\displaystyle P(A \cap B) = P(B\cap A) = P(A) \cdot P(B|A) = \frac{5}{10}\cdot \frac{4}{9}$ .

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2 years ago

Explain how solving 2x+16=14 different from solving 2x+16=x+14

vladimir2022 [97]

The difference between 2x+16=14 than 2x+16=x+14 is that you would have to solve x in two different ways like finding the first equation another way than to the second equation ( I think ).

4 0

3 years ago

mr and mrs gracia took their three children to see a matinee on saturday. they spent a total of 55.50, which included 29.95 at t

andrezito [222]

First, you would subtract 29.95 from 55.50, and you get 25.55. because 5 people went, and the cost for each was the same, you would divide 25.55 by five, and get $5.11 per person.

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2 years ago

Factor 11x(x-2)+3(x-2)

Stells [14]

Answer:

(11x+3)(x-2)

Step-by-step explanation:

11x2-22x+3x-6

11x-19x-6

4 0

3 years ago

Read 2 more answers