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irga5000 [103]
3 years ago
13

Need help with a math question

Mathematics
1 answer:
Lilit [14]3 years ago
6 0

Answer:

d =\sqrt{(b-0)^2 +(c-a)^2}

Step-by-step explanation:

We know that the distance between two points is calculated using the following formula

d =\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}

In this case we look for the RS distance

Then

The starting point is: (0, a)

The final point is (b, c)

So

x_2 = b\\x_1 = 0\\y_2 = c\\y_1=a

The distance is:

d =\sqrt{(b-0)^2 +(c-a)^2}

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Kwasi has earned $60 in babysitting money. He spends 40% of this money buying drinks for himself and two friends at Starbucks. H
mart [117]

Answer: Yes

Step-by-step explanation:

Given

Kwasi earned \$60 in babysitting

He spends 40% of the money in buying drinks

Money spend is given by

\Rightarrow 60\times 40\%\\\Rightarrow \$24\\\text{Remaining amount is}\\\Rightarrow 60-24=\$36

So, Kwasi has enough money left to buy a skateboard.

3 0
2 years ago
A. dashed line, shade below
Ronch [10]

Answer:

the answer is A

Step-by-step explanation:

3 0
3 years ago
State whether the lines are parallel, perpendicular,or neither.
cluponka [151]

Answer:

Please check the explanation.

Step-by-step explanation:

  • Two lines are parallel if their slopes are equal.
  • Two lines are perpendicular if the product of their slope is -1

We also know that the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept

Given the lines

1)

  • y = 6х - 3

Comparing with y=mx+b, the slope of y = 6х - 3:

m₁=6  

  • y = - 1/6x + 7

Comparing with y=mx+b, the slope of y = - 1/6x + 7:

m₂=-1/6

As

m₁ × m₂ = -1

6 ×  - 1/6 = -1

-1 = -1

Thus, the lines y = 6х - 3 and y = - 1/6x + 7 are perpendicular.

2)

  • y = 3x + 2

Comparing with y=mx+b, the slope of y = 3x + 2:

m₁=3  

  • 2y = 6x - 6

simplifying to write in slope-intercept form

y=3x-3

Comparing with y=mx+b, the slope of y=3x-3:

m₂=3

As the slopes of y = 3x + 2 and 2y = 6x - 6 are equal.

i.e. m₁ = m₂ → 3 = 3

Thus, the lines y = 3x + 2 and 2y = 6x - 6 are paralle.

3)

  • 8x - 2y = 3

simplifying to write in slope-intercept form

y = 4x - 3/2

Comparing with y=mx+b, the slope of y = 4x - 3/2:

m₁=4  

  • x + 4y = - 1

simplifying to write in slope-intercept form

y=-1/4x-1/4

Comparing with y=mx+b, the slope of y=-1/4x-1/4:

m₂=-1/4

As

m₁ × m₂ = -1

4 ×  - 1/4 = -1

-1 = -1

Thus, the lines 8x - 2y = 3 and x + 4y = - 1 are perpendicular.

4)

  • 3x+2y = 5

simplifying to write in slope-intercept form

y = -3/2x + 5/2

Comparing with y=mx+b, the slope of y = -3/2x + 5/2:

m₁=-3/2  

  • 3y + 2x = - 3

simplifying to write in slope-intercept form

y = -2/3x - 1

Comparing with y=mx+b, the slope of y = -2/3x - 1:

m₂=-2/3

As m₁ and m₂ are neither equal nor their product is -1, hence the lines neither perpendicular nor parallel.

5)

  • y - 5 = 6x

simplifying to write in slope-intercept form

y=6x+5

Comparing with y=mx+b, the slope of y=6x+5:

m₁=6  

  • y - 6x = - 1

simplifying to write in slope-intercept form

y=6x-1

Comparing with y=mx+b, the slope of y=6x-1:

m₂=6

As the slopes of y - 5 = 6x and y - 6x = -1 are equal.

i.e. m₁ = m₂ → 6 = 6

Thus, the lines y - 5 = 6x and y - 6x = -1 are paralle.

6)

  • y = 3х + 9

Comparing with y=mx+b, the slope of y = 3х + 9:

m₁=3  

  • y = -1/3x - 4

Comparing with y=mx+b, the slope of y =  1/3x - 4:

m₂=1/3

As m₁ and m₂ are neither equal nor their product is -1, hence the lines neither perpendicular nor parallel.

8 0
2 years ago
Factor this expression completely mr + ns - nr - ms
Talja [164]
(m - n)(r - s) Hope this helps and heve a nice day!

8 0
3 years ago
Read 2 more answers
Please help
Andreyy89

9514 1404 393

Answer:

  y -1 = -1(x -2)

Step-by-step explanation:

The slope of the line through the two points can be found from the slope formula:

  m = (y2 -y1)/(x2 -x1)

  m = (5 -1)/(-2 -2) = 4/-4 = -1

The point-slope equation for a line through point (h, k) with slope m is ...

  y -k = m(x -h)

You have (h, k) = (2, 1) and m = -1. Putting these values into the form gives ...

  y -1 = -1(x -2)

_____

<em>Additional comment</em>

Your problem statement already has two of the three values filled in, so you only need to enter the x-coordinate of the first point: 2.

5 0
3 years ago
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